First, we find the slope of the given line.
<span>3x − 4y = 7
-4y = -3x + 7
y = (3/4)x - 7/4
The slope of the given line is 3/4.
The slope of the parallel line is also 3/4.
Now we need the equation of the line that has slope 3/4 and passes through point (-4, -2),
We use the point-slope form of the equation of a line.
y - y1 = m(x - x1)
y - (-2) = (3/4)(x - (-4))
y + 2 = (3/4)(x + 4) <---- check option E. Is the fraction 3/4 not there?
y + 2 = (3/4)x + 3
y = (3/4)x + 1
4y = 3x + 4
3x - 4y = -4 <------ this is choice B.
</span>
Answer:
104°
Step-by-step explanation:
The straight line for
forms an angle of 180°
Therefore,




Answer:
The equation above represents the total time the play director spent preparing for a play.
Step-by-step explanation:
The time spent by the play director for preparing for a play is, 190 hours.
Of these 190 hours, the director spent varying amounts of time attending 35 rehearsals for the play.
Let the varying amounts of time be denoted by, <em>x</em>.
The director also spent 3/4th of an hour, i.e. 45 minutes, on other responsibilities related to the play.
The equation provided is:

The equation above represents the total time the play director spent preparing for a play.