Question

Anyone know the answer to this algebra 2 question?

Answer 1

Answer:

The answer to your question is: I(dB) = 320

Step-by-step explanation:

Data

I(dB) = 10log($\frac{I}{Io}$)

I = intensity of a given sound

Io = hearing intensity

if I = 10³²(Io) find I(dB)

Process

Substitute the value of I in the equation given and simplify using logarithms rules.

                     l(dB) = $10 log \frac{10^{32}Io }{Io}$

Eliminate Io

                    I(dB) = 10 log (10³²)

Use the rule of powers in logarithms

                   I(dB) = 10(32)log(10)

                   l(dB) = 320(1)

                   I(dB) = 320