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den301095 [7]
3 years ago
11

Solve the system of equations: y= 3x y= x^2 - 4

Mathematics
1 answer:
OLga [1]3 years ago
5 0

Answer:

x=-1\\y=-3\\\\x=4\\y=12

Step-by-step explanation:

Make both equations equal to each other and solve for the variable x:

y=y\\3x=x^2-4\\x^2-3x-4=0\\

Find two numbers that when you add them you get -3 and the product of both numbers be -4. These numbers are 1 and -4. Then:

(x+1)(x-4)=0\\\\x+1=0\\x=-1\\\\x-4=0\\x=4

Substitute these values into one the original equations and solve for y:

y=3(-1)\\y=-3\\\\y=3(4)\\y=12

Therefore, you get that:

x=-1\\y=-3\\\\x=4\\y=12

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Step-by-step explanation:

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4 0
3 years ago
Pls help me!! I just need help on both of the following questions, a-d on each
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I'll do a and e on the first one to show you how to do it

Then See if you can do the rest

a. 6(-3)<span><span>
</span></span>
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So 6 × 3 = 18 ; but since there is a negative on the 3 your answer will be -18

e. -20 ÷ 5

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You do b, c, d, and f on the first question. Tell me what you get and we'll go from there

</span>Now for the second question <span>

</span>I will do a and d to show you how to do this then you do the rest<span> (I'm inserting a picture with these)

</span>a. 4(-2 \frac{1}{3}) + 7 \frac{1}{6}
First go ahead and turn the fractions into improper fractions, this makes them a bit easier to work with. When multiplying fractions; they do not need a common denominator, all you do is multiply top by top and bottom by bottom.<span>
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</span>d. (-4.25)(2) + (-4.25)(-2)
remember from the first problem a negative times a positive gives you a negative<span>

but when you times a negative by a negative you get a positive


Now you try b and c; let me know what you get, and we'll go from there!

</span>

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Answer:

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Step-by-step explanation:


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Read 2 more answers
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