Total area=<br> Help me please!! Thanks so much

One leg of a right triangle measures 10 inches while the other leg measures sqrt(21) Inches . What is the length of hypotenuse ?

Sveta_85 [38]

Answer:

$\sqrt{541} \\$ =x

Step-by-step explanation:

10^2+21^2=x^2]

100+441=x^2

541=x^2

$\sqrt{541} \\$ =x

4 0

4 years ago

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Describe how each graph is related to the graph of y = |x).

grigory [225]

Answer:stumped

Step-by-step explanation:

I admit it. I’m kinda stumped

3 0

3 years ago

Simplify <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20-%2048%7D%20" id="TexFormula1" title=" \sqrt{ - 48} " alt=" \sqrt

slava [35]

Answer:

4i*sqrt(3)

Step-by-step explanation:

Break into prime factors.

48:2 * 2 * 2 * 2 * 3

sqrt(- 2 * 2 * 2 * 2 * 3) for every pair of factors take 1 out of the brackets and throw the other one away.

2 * 2 sqrt(-3) The square root of a minus is i

2 * 2 * i * sqrt(3)

4i * sqrt(3) Answer

7 0

3 years ago

Which expression is equal to...

salantis [7]

The answer is the one that has a denominator of X-5 :)

3 0

3 years ago

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A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo

defon

Answer:

a) The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

b) $P(X$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

$P(X$

c) $P(X>10.5)$

And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

Step-by-step explanation:

For this case we define the random variable X=quantity put in each bag , and we know that the distribution for X is given by:

$X \sim Unif (a= 10, b =12)$

Part a

The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

Part b

For this case we want this probability:

$P(X$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

$P(X$

Part c

For this case we want this probability:

$P(X>10.5)$

And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

3 0

4 years ago

Total area= Help me please!! Thanks so much