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3 years ago

6x+8y=30

1 answer:

8 0

First substitute .5x in for y to get a solvable equation. You should get 6x+8(.5x)=30. Then multiply 8 times .5 to get 6x+4x=30. Then combine like terms (6x+4x) to get 10x=30 and divide both sides by 10 to get x=3. Then plug this x value (3) into the other equation (y=.5x) to find the value of y. Y=.5(3) so y=1.5. Therefore the answer is B.

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What is the slope of a line that is perpendicular to 3x+2y=14

djyliett [7]

Answer:

2/3

Step-by-step explanation:

7 0

3 years ago

A jet plane has a takeoff speed of vto = 75 m/s and can move along the runway at an average acceleration of 1.3 m/s2. If the len

pishuonlain [190]

Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m

time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s

the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s

Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.

6 0

3 years ago

Read 2 more answers

A private ship carries two types of cargo: large crates and extra-large crates. Each type of crate weighs a specific amount.

Arisa [49]

Answer:

G. 32

Step-by-step explanation:

32 x 335 = 10720

16,100 - 10720 = 5380/190 = 28.3157894737

275 x 32 = 8800

18,800 - 8800 = 10,000/400 = 25 (This is the closer).

30 x 335 = 10,050

16,100 - 10,050 = 6050/190 = 31.8421052632

30 x 275 = 8250

18,800 - 8250 = 10550/400 = 26.375 (Same reason why it does't work)

25 x 335 = 8375

16,100 - 8375 = 7725/190 = 40.6578947368

25 x 275 = 6875

18,800 - 6875 = 11925/400 = 29.8125

24 x 335 = 8040

16,100 - 8040 = 8060/190 = 42.4210526316

24 x 275 = 6600

18,800 - 6600 = 12200/400 = 30.5

8 0

2 years ago

snow_tiger [21]

Answer: 76

Step-by-step explanation:

47+3= 50

19+7=26

50+26=76

Where's the Bar Diagram?

Hope this Helps!

4 0

3 years ago

Karl is putting a frame around a rectangular photograph. The photograph is 14 inches long and 10 inches wide, and the frame is t

Sergeu [11.5K]

<h2>The area of the framed photograph = 1156 $inch^{2}$ </h2>

Step-by-step explanation:

Given,

The length of photograph (l) = 14 inches and

The breadth of photograph (b) = 10 inches

To find, the area of the framed photograph = ?

We know that,

The area of the framed photograph = (l + 2b)(l + 2b)

= (14 + 2 × 10) (14 + 2 × 10) $inch^{2}$

= (14 + 20) (14 + 20) $inch^{2}$

= (34) (34) $inch^{2}$

= 1156 $inch^{2}$

∴ The area of the framed photograph = 1156 $inch^{2}$

8 0

3 years ago