The value of the car after 10 years is $5557.8.
What is depreciation?
Depreciation refers to the reduction in the value of an asset over time and such valued reductions are reflected in the Balance sheet at the year ended.
Given
A new car is purchased for 23700 dollars.
The value of the car depreciates at 13.5% per year.
According to the question,
The value of the car depreciates therefore the amount of the car is determined by the formula,
Where, P = $23700, r = 13.5% and t =10 years
Substitute all the values in the formula,
Hence, the value of the car after 10 years is $5557.8.
To know more about Percentages click the link given below.
brainly.com/question/14675742
What z score in a normal distribution has 33% of all score above it?
Answer: A z score which has 33% of all scores above it, will have 67% of all scores below it.
To find the required z score, we need to find the z value corresponding to probability 0.67.
Using the standard normal table, we have:
Therefore, the z score = 0.44 has 33% of all score above it.
So do you need it as a percent or a fraction?
Average (mean) = (sum of all the data) / (# of data)
sum of all the data = (average)(# of data)
Thus for 100 students with an average of 93,
sum of all data = (93)(100) = 9300
and for 300 students with an average of 75,
sum of all data = (75)(300) = 22500
Therefore you would expect the overall average to be
(9300 + 22500) / (100 + 300) = 79.5 %
Now if there are x # of advanced students and y # of regular students, then
x + y = 90 (total # of students) and 93x + 75y = 87(x + y) (overall average)
The second equation can be simplified to x - 2y = 0
Subtracting the two equations yields
x = 60 and y = 90
Therefore you would need 60 advanced and 30 regular students.
You can convert them to decimals and multiply. Remember when using decimals, it is over 10 or 100 <span />
