Galactic Rotation Speed. We are located about 27,000 light-years from the galactic center and we orbit the center about once eve
1 answer:
Answer:
speed = 796142.197 km/hr
Step-by-step explanation:
solution
we consider here orbit around galactic center is circular so
circumference formula will be here
circumference C = 2πr ........1
here we know r = 27000
so
circumference C = 2 π × 27000
C = 169560 light year
so
we travel 169560 light year in 230000000 years
so distance will be
distance =
distance = 0.00073721 light year/year
and we know 1 year = 8760 hours
so 1 light year = 9.46027 × km
so
sped of moving is
speed = 0.00073721 × 9.46027 × km/hr
speed = 796142.197 km/hr
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Answer:
The Possible dimension of the ring could be;
20 ft × 60 ft
25 ft × 48 ft
30 ft × 40 ft
60 ft × 20 ft
48 ft × 25 ft
40 ft × 30 ft
Step-by-step explanation:
Given:
Number of skaters = 30
Area for each skater = 40 sq ft
We need to find the dimension of rectangular ring the are going to build.
Now we know that they building the skating ring such that they all can use at same time.
Hence if the all use at same time then we will find the total area first.
Total area can be calculated by multiplying Number of skaters with area required for each skaters.
Framing the equation we get;
Total area =
Hence The total area of the rectangular ring would be 1200 sq. ft.
Now we know that Total area is equal to product of length and width.
1200 can be written as = 20 × 60, 25 × 48, 30 × 40,60 × 20,48 × 25,40 × 30
Hence the Possible dimension of the ring could be;
20 ft × 60 ft
25 ft × 48 ft
30 ft × 40 ft
60 ft × 20 ft
48 ft × 25 ft
40 ft × 30 ft