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seraphim [82]
2 years ago
7

Jarred sells DVDs. His inventory shows that he has a total of 3,500 DVDs. He has 2,342 more contemporary titles than classic tit

les. Let x represent the number of contemporary titles and y represent the number of classic titles. The system of equations models the given information for both types of DVDs.
x + y = 3,500

x – y = 2,342

Solve the system of equations. How many contemporary titles does Jarred have?
Mathematics
1 answer:
uysha [10]2 years ago
5 0

The number of contemporary titles and classic titles in Jarred DVDs collection is 2,921 and 579 respectively.

<h3>Simultaneous equation</h3>

Simultaneous equation is an equation which involves the solving for two unknown values at the same time.

  • number of contemporary titles = x
  • number of classic titles = y

x + y = 3,500

x – y = 2,342

Add both be equation

x + x = 3,500 + 2,342

2x = 5,842

x = 5,842 ÷ 2

x = 2,921

Substitute x = 2,921 into

x – y = 2,342

2,921 - y = 2, 342

-y = 2,342 - 2,921

-y = -579

y = 579

Therefore, the number of contemporary titles and classic titles in Jarred DVDs collection is 2,921 and 579 respectively.

Learn more about simultaneous equation:

brainly.com/question/17127685

#SPJ1

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Answer: 200

Step-by-step explanation:

Number of numbers counted by Alex;

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Number of numbers counted by Matthew;

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Numbers that both of them counted = 600 - 400

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The size of a typical city park is about 5 acres, or 217,800 square feet. If a developer plans to
pshichka [43]

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<h3>What is a percentage?</h3>

The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:

P = \frac{a}{b} \times 100\%

In this problem, there will be two courts of 5,000 square feet each, totaling 10,000 square feet. The remainder 207,800 square feet will be used for other activities, hence the percentage is given by:

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More can be learned about the percentage concept at brainly.com/question/10491646

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2 years ago
13- (8x - 5) – 16x
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Answer:

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A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms . The ball's height h (in meters) af
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A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms

Balls height h= 2 +9t -5t^2

To find all values of t for which the ball's height is 3 meters

We plug in 3 for h and solve for t

h= 2 +9t -5t^2

3 = 2 +9t -5t^2

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