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3 years ago

△QRS is rotated about point P to △Q′R′S′ .

Mathematics

1 answer:

Sedbober [7]3 years ago

4 0

Answer:

As Given △QRS is rotated about point P to △Q′R′S′ .

As we know after rotation by any angle of pre-image neither the shape nor size of the image changes, the image after rotation is congruent to pre image.

Out of the options given

→The corresponding lengths, from the point of rotation, between the pre-image and the image are preserved.

→The corresponding angle measurements in each triangle between the pre-image and the image are preserved.

are true.

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Scorpion4ik [409]

El mínimo común múltiplo de 20 14 y 17 es 1.

17 es un número primo, y su únicos múltiplos son 17 y 1.

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3 years ago

Simplify (4a^m+3)^3*(1/16a^1-m)^2

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2 years ago

Principle = 30,000 Time = 4 years Rate = 30 Then find the simple interest ?

Nutka1998 [239]

Answer:

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Given:}}}}}}\end{gathered}$

${\dashrightarrow \sf{Principle = Rs.30000}}$
${\dashrightarrow \sf {Time = 4 \: years}}$
$\dashrightarrow \sf{Rate = 30\%}$
$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{To Find:}}}}}}\end{gathered}$

$\dashrightarrow{\sf{Simple \: Interest }}$

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Using Formula:}}}}}}\end{gathered}$

$\dag{\underline{\boxed{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}}$

Where

$\dashrightarrow{\sf{S.I = Simple \: Interest }}$
${\dashrightarrow{\sf{P = Principle }}}$
${\dashrightarrow{\sf{ R = Rate }}}$
${\dashrightarrow{\sf{T = Time}}}$

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Solution:}}}}}}\end{gathered}$

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{P \times R \times T}{100}}}}}}$

Substituting the values

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{30000 \times 30\times 4}{100}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{30000 \times 120}{100}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{3600000}{100}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{\cancel{\dfrac{3600000}{100}}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{Rs.36000}}}}}$

${\dag{\underline{\boxed{\sf{ S.I ={Rs.36000}}}}}}$

Henceforth,The Simple Interest is Rs.36000..

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Learn More:}}}}}}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

8 0

3 years ago

Read 2 more answers

Over the course of a month, a person’s weight decreases. What type of relationship is this?

Hoochie [10]

It is a negative relationship

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3 years ago

Read 2 more answers

You are given a line that has a slope of 4 and passed through the point (3/8, 1/2). Which statements about the question of the l

alexgriva [62]

Answer:

Statement 1, 2 and 4 are true where as statement 3 is not true.

Step-by-step explanation:

Statement 1: The y-intercept is -1

Point (3/8, 1/2)

Slope = m = 4

y = mx + c

1/2 = 4(3/8) + c

1/2 = 3/2 + c

1/2 = 3/2 + 2c/2

-2 = 2c

c = -1

This statement is true as the y-intercept is -1.

Statement 2: The slope intercept equation is y= 4x - 1

slope = m = 4

y-intercept = c = -1

y = mx + c

y = 4x - 1

This statement is true as the slope intercept equation is y= 4x -1

Statement 3: The point slope equation is y - 3/8 = 4 (x - 1/2)

Point slope equation: y - y1 = m (x - x1)

Points: (x, y) (3/8, 1/2)

y1 = 1/2

x1 = 3/8

Slope = m = 4

y - 1/2 = 4 (x - 3/8)

This statement is not true as the slope intercept equation is y - 1/2 = 4 (x - 3/8) instead of y - 3/8 = 4 (x - 1/2).

Statement 4: The point (3/8, 1/2) corresponds to (x1, y1) in the point slope form of the equation

This statement is true as shown in statement 3's explanation where x1 = 3/8 and y1 = 1/2

6 0

3 years ago