Answer:
Parent's share would be : 28%
Step-by-step explanation:
Cost of the computer = $2000
Anya's share = $1200
Brother's share = $240
Parents paid rest. That will be : 2000 - 1200 - 240 = $560
Percentage of parents share :
![\frac{560}{2000} \times 100 = 28 \%](https://tex.z-dn.net/?f=%5Cfrac%7B560%7D%7B2000%7D%20%5Ctimes%20100%20%3D%2028%20%5C%25)
Converse (switch p and q)
If an angle is obtuse, then it measures 128°
This is false (a 127° angle is obtuse, but it does not measure 128°)
_____________________________________________________________
Inverse (negations of p and q)
If an angle does not measure 128°, then it is not obtuse
This is false (a 127° angle does not measure 128°, but it is obtuse)
_____________________________________________________________
Contrapositive (negations of p and q, then switch their places)
If an angle is not obtuse, it does not measure 128°
This is true (any 128° is obtuse; no exceptions)
G(x) would have to be -->7 units.
The relationship between f(x) and s(x) where s(x)=af(x-b)+z is that g(x) is f(x) stretched by the reciprocal of a, b is the liar (all x values go up if b goes down and visa versa), and it moves up z units.
Answer:
The correct option is 4.
Step-by-step explanation:
Given information:
Bring lunch : 46 males, 254 females
Buy lunch : 176 males, 264 females
Total number of peoples is
![46+254+176+264=740](https://tex.z-dn.net/?f=46%2B254%2B176%2B264%3D740)
Total number of males is
![46+176=222](https://tex.z-dn.net/?f=46%2B176%3D222)
The probability of male is
![P(Male)=\frac{Males}{Total}=\frac{222}{740} =0.3](https://tex.z-dn.net/?f=P%28Male%29%3D%5Cfrac%7BMales%7D%7BTotal%7D%3D%5Cfrac%7B222%7D%7B740%7D%20%3D0.3)
Since probability of males is 0.3, therefore options A and C are incorrect.
Total number of persons who buys lunch is
![176+264=440](https://tex.z-dn.net/?f=176%2B264%3D440)
The probability of persons who buys lunch is
![P(\text{Buys lunch})=\frac{\text{Buys lunch}}{Total}=\frac{440}{740} =\frac{22}{37}](https://tex.z-dn.net/?f=P%28%5Ctext%7BBuys%20lunch%7D%29%3D%5Cfrac%7B%5Ctext%7BBuys%20lunch%7D%7D%7BTotal%7D%3D%5Cfrac%7B440%7D%7B740%7D%20%3D%5Cfrac%7B22%7D%7B37%7D)
We need to find the probability of P(male | buys lunch).
According to the conditional probability, we get
![P(\frac{A}{B})=\frac{P(A\cap B)}{P(B)}](https://tex.z-dn.net/?f=P%28%5Cfrac%7BA%7D%7BB%7D%29%3D%5Cfrac%7BP%28A%5Ccap%20B%29%7D%7BP%28B%29%7D)
P(male | buys lunch)![=\frac{P(\text{male }\cap \text{ buys lunch})}{P(\text{buys lunch})}](https://tex.z-dn.net/?f=%3D%5Cfrac%7BP%28%5Ctext%7Bmale%20%7D%5Ccap%20%5Ctext%7B%20buys%20lunch%7D%29%7D%7BP%28%5Ctext%7Bbuys%20lunch%7D%29%7D)
P(male | buys lunch)![=\frac{\frac{176}{740}}{\frac{22}{37}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Cfrac%7B176%7D%7B740%7D%7D%7B%5Cfrac%7B22%7D%7B37%7D%7D)
P(male | buys lunch)![=\frac{2}{5}=0.4](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%7D%7B5%7D%3D0.4)
Therefore the correct option is 4.