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Soloha48 [4]
2 years ago
9

The formation of protons over neutrons (thus producing about a 7:1 ratio) was favored in the early universe because:____.

Chemistry
1 answer:
tatiyna2 years ago
7 0

Because it requires more energy to create a neutron from a proton than it does to create a proton from a neutron, protons were formed more frequently than neutrons in the early universe. The correct answer is option b.

To find the answer, we need to know more about the early universe.

<h3>How the formation of proton over neutrons was favored in the early universe?</h3>
  • A neutron is produced with greater energy than a proton.
  • However, later on, some of the protons were changed into neutrons.
  • Contrary to some claims, the proton is a stable particle that never decays, but the neutron is unstable outside of the nucleus and decays with a half life of around 10.5 minutes.
  • However, very few would have had time to decay on the timeline you mention in your question.
  • Every matter particle should have been accompanied by an antimatter particle, and every proton, neutron, and electron, by an anti-neutron and a positron, respectively.
  • Where did all the antimatter go is the great mystery. There have been a few attempts to explain this, but they have failed.

Thus, we can conclude that, the correct answer is option b.

Learn more about the early universe here:

brainly.com/question/28130096

#SPJ1

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Lead(II) nitrate is added slowly to a solution that is 0.0800 M in Cl− ions. Calculate the concentration of Pb2+ ions (in mol /
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Answer:

[Pb^{2+}]=3.9 \times 10^{-2}M

this is the concentration required to initiate precipitation

Explanation:

PbCl_2  ⇄ Pb^{2+}+2Cl^-

Precipitation starts when ionic product is greater than solubility product.

Ip>Ksp

Precipitation starts only when solution is supersaturated because solution become supersaturated then it does not stay in this form and precipitation starts itself only solution become saturated.

This usually happens when two solutions containing separate sources of cation and anion are mixed together and here also we are mixing lead (||)nitrate solution(source of lead(||)) into the Cl- solution.

Ip=[Pb^{2}][2Cl^-]^2=Ksp

Ksp=2.4\times 10^{-4}

lets solubility=S

[Pb^{2+}] = S

[Cl^-]=2S

Ksp=[Pb^{2+}]\times [Cl^-]^2

Ksp=S \times (2S)^2

Ksp=4S^3

S=\sqrt[3]{\frac{Ksp}{4} }

S=3.9\times 10^{-2}

[Pb^{2+}]=3.9 \times 10^{-2}M this is the concentration required to initiate precipitation

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