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Zarrin [17]
3 years ago
12

Who is interested in a middle schooler?

Chemistry
1 answer:
belka [17]3 years ago
6 0

Answer:

I think that middle school teachers are interested in teaching middle schoolers.

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In each row check off the boxes that apply to the highlighted reactant. reaction The highlighted reactant acts as a... (check al
tekilochka [14]

The given question is incomplete. The complete question is :

In each row check off the boxes that apply to the underlined reactant. The underlined reactant acts as a... (check all that apply)

1. HCH_3CO_2(aq)+NH_3(aq)\rightarrow CH_3COO^-(aq)+NH_4^+(aq)

here underlined is HCH_3CO_2

A. Brønsted-Lowry acid

B. Brønsted-Lowry base

C. Lewis acid

D. Lewis base

2. BH_3(aq)+NH_3(aq)\rightarrow BH_3NH_3(aq)

Here underlined is NH_3

A. Brønsted-Lowry acid

B. Brønsted-Lowry base

C. Lewis acid

D. Lewis base

3. HNO_2(aq)+C_2H_5NH_2(aq)\rightarrow NO_2^-(aq) + C_2H_5NH_3^+(aq)

Here underlined is C_2H_5NH_2

A. Brønsted-Lowry acid

B. Brønsted-Lowry base

C. Lewis acid

D. Lewis base

Answer: 1. Brønsted-Lowry acid

2. Lewis base

3. Brønsted-Lowry base

Explanation:

According to the Bronsted Lowry conjugate acid-base theory, an acid is defined as a substance which donates protons and a base is defined as a substance which accepts protons.

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

1.  HCH_3CO_2(aq)+NH_3(aq)\rightarrow CH_3CO^{2-}(aq)+NH_4^+aq)

As HCH_3CO_2(aq) is donating a proton , it acts as a bronsted acid.

2. BH_3(aq)+NH_3(aq)\rightarrow BH_3NH_3(aq)

As NH_3 contains a lone pair of electron on nitrogen , it can easily donate electrons to BH_3 and act as lewi base.

3.  HNO_2(aq)+C_2H_5NH_2(aq)\rightarrow NO_2^-(aq) + C_2H_5NH_3^+(aq)

As C_2H_5NH_2(aq) is accepting a proton , it acts as a bronsted base.

7 0
3 years ago
7. Diethyl ether burns in air according to the following equation. C4H10O(l) + 6O2 (g) → 4CO2 (g) + 5H2O(l) If 7.15 L of CO2 is
iren [92.7K]

From the stoichiometry of the combustion reaction, we can see that 7.4 L of oxygen is consumed.

<h3>What is combustion?</h3>

Combustion is a reaction in which a substance is burnt in oxygen. The equation of the reaction is; C4H10O(l) + 6O2 (g) → 4CO2 (g) + 5H2O(l)

We can obtain the number of moles of CO2 from;

PV = nRT

n = 1.02 atm * 7.15 L/0.082 atm LK-1mol-1 * (125 + 273) K

n = 7.29 /32.6

n = 0.22 moles

If 6 moles of oxygen produces 4 moles of CO2

x moles of oxygen produces 0.22 moles of CO2

x = 0.33  moles

1 mole of oxygen occupies 22.4 L

0.33 moles of oxygen occupies 0.33 moles *  22.4 L/ 1 mole

= 7.4 L of oxygen

Learn more about stoichiometry: brainly.com/question/13110055

#SPJ1

6 0
3 years ago
- a) write the formula unit of calcium fluoride.
8090 [49]

Answer:

hope this image is helpful for you

5 0
3 years ago
One mechanism for the synthesis of ammonia proposes that N₂ and H₂ molecules catalytically dissociate into atoms:N₂ ⇆ 2N(g) log
Pavlova-9 [17]

The artificial fixation of nitrogen (N2) has enormous energy, environmental, and societal impact, the most important of which is the synthesis of ammonia (NH3) for fertilizers that help support nearly half of the world's population.

<h3>Artificial fixation of nitrogen</h3>

a) The equilibrium constant expression is Kp​=PCH4​​ PH2​ O​P CO​×PH 2​3​​.

(b) (i) As the pressure increases, the equilibrium will shift to the left so that less number of moles are produced.

(ii) For an exothermic reaction, with the increase in temperature, the equilibrium will shift in the backward direction.

(iii) When a catalyst is used, the equilibrium is not disturbed. The equilibrium is quickly attained

To learn more about equilibrium constant visit the link

brainly.com/question/10038290

#SPJ4

6 0
2 years ago
Given the balanced chemical equation, SiO2(s) + 4 HF(g) → SiF4(g) + 2 H2O(l) ΔH°rxn = −184 kJ Determine the mass (in grams) of H
Ostrovityanka [42]

Answer:

mass HF = 150.05 g

Explanation:

  • SiO2(s) + 4HF(g) → SiF4(g) + 2H2O(l)

⇒ Q = (ΔH°rxn * mHF) / (mol HF * MwHF )

∴ MwHF = 20.0063 g/mol

∴ mol HF = 4 mol

∴ ΔH°rxn = - 184 KJ

∴ Q = 345 KJ

mass HF ( mHF ):

⇒ mHF = ( Q * mol HF * MwHF ) / ΔH°rxn

⇒ mHF = ( 345 KJ * 4mol HF * 20.0063 g/mol ) / 184 KJ

⇒ mHF = 150.05 g HF

3 0
4 years ago
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