Answer: Concentration of N₂ is 4.8.
M.
Explanation: 
is a constant of equilibrium and it is dependent of the concentrations of the reactants and the products of a balanced reaction. For
N2(g) + 2 O2(g) ⇄ 2 NO2(g)
= ![\frac{[NO2]^{2} }{[N2][O2]^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5BNO2%5D%5E%7B2%7D%20%7D%7B%5BN2%5D%5BO2%5D%5E%7B2%7D%20%7D)
From the question concentration of NO2 is twice of O2:
[NO2] = 2[O2]
Substituting this into :
= ![\frac{[2O2]^{2} }{[N2][O2]^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5B2O2%5D%5E%7B2%7D%20%7D%7B%5BN2%5D%5BO2%5D%5E%7B2%7D%20%7D)
8.3.
= ![\frac{4O2^{2} }{[N2].O2^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B4O2%5E%7B2%7D%20%7D%7B%5BN2%5D.O2%5E%7B2%7D%20%7D)
[N2] = 
[N2] = 
[N2] = 4.8.
The concentration of N2 in the equilibrium is [N2] = 4.8.M.
Answer:
The symbol of isotopes used for blood flow analysis is 
<u>Explanation:
</u>
- Isotopes are the substances that exhibit the same atomic number but has a different mass number of an element.
- The atomic number explains the number of protons present in the element and mass number explains the number of neutrons available in the element.
- For blood flow analysis, the isotope element is cerium-141 and it is used in the chemical examination of blood flow particles.
- Symbol used for this isotope is
, where 141 indicates the amount of mass present and 58 indicates the proton number and 83 indicates neutron number present in that element.
- The amount of mass in an atom is calculated by the sum of protons and neutrons present in it. Thus mass of isotope is 141 obtained by the sum of 58 protons and 83 neutrons present in that isotope.
Answer:
i am pretty sure it is compound
Answer:
option C= 12.40
Explanation:
Formula:
pH + pOH = 14
First of all we will calculate the pH.
pH = - log [H⁺]
pH = - log [0.025]
pH = - (-1.6)
pH = 1.6
Now we will put the values in formula,
pH + pOH = 14
pOH = 14-pH
pOH = 14 -1.6
pOH = 12.4
The pOH of solution is 12.4.
The answer is the 3. Hope this helped!
