A major drawback with lot-for-lot sizing is?

At the beginning of June, the Jones Company had two jobs in the Work in Process Inventory account. Job A had costs of $500 alrea

KatRina [158]

Answer:

Work in Process Inventory account balance on June 30 is $950.

Explanation:

Here i will calculate the balance of Work in Process Inventory account using missing figure technique in Work In Process T - Account.

Calculation of Work in Process Inventory account balance

Work In Process T - Account

Debit :

Beginning Work in Process (Job A) $500

Beginning Work in Process (Job B) $350

Manufacturing Costs incurred (Job A) $750

Manufacturing Costs incurred (Job B) $600

Totals $2,200

Credit :

Transferred to Finished Goods (Job A) $1,250

Ending Work In Process (Job B) (Balancing figure) $950

Totals $2,200

3 0

3 years ago

] Bear Co. prepares its statement of cash flows using the indirect method. Bear sold equipment with a carrying value of $500,000

Svetlanka [38]

Answer:

The transaction in the operating and investing activities sections of its statement of cash flows is a loss of $400,000 and the sale of equipment $400,000

Explanation:

Operating Activity: It includes all those activities which are related to the changes in the working capital that mean increase or decrease in currents assets and current liabilities. Moreover, it also includes loss/ gain on sale of fixed assets and depreciation, etc.

Investing activity: It records those transactions which include sale and purchase of fixed assets.

So, by going through the meaning of operating activity and investing activity we get to know that the operating activity record a loss of $100,000 which comes from Carrying value - sales value which is added to the net income.

And, the investing records sale price of equipment which is $400,000

Hence, the transaction in the operating and investing activities sections of its statement of cash flows is a loss of $400,000 and the sale of equipment $400,000

6 0

4 years ago

Read 2 more answers

Baseball's increasing global popularity may be attributed to

mars1129 [50]

The Baseballâ€™s growing popularity could be attributed to relocation diffusion, which means people relocate and establish other countryâ€™s custom in another. in recent decades many cultures that have been known to be found in the developed world such as hip hop has come to stay in other countries as people travel around the world and take other peopleâ€™s culture to another place.

5 0

3 years ago

One important indicator of how well a company's present strategy is working is whether a.its strategy is built around at least t

ad-work [718]

Answer:

B

Explanation:

the company is achieving its financial and strategic objectives and whether it is an above-average industry performer.

5 0

4 years ago

A well insulated 3-m X 4-m X 6-m room initially at 7 degrees C is heated by the radiator of a steam heating system. The radiator

poizon [28]

Answer:

The average temperature of air in 45 minutes is 10.74°C

Explanation:

Given

Time t = 45 minutes

Initial Air Temperature, T1 = 7°C

Fan work W = 120W

Radiator Volume = V1 = 15L

Initial Steam Pressure = P1 = 200kPa

Initial Steam Temperature = Ts1 = 200°C

Final Steam Pressure = P2 = 100kPa

The radiator is our system.

We take the system as a close system.

The energy balance is given as follows

-Qout = ∆U

-Qout = m(u2 - u1)

Calculating u2

From steam table (see attachment below)

At P1 and Ts1

P1 = 200kPa, Ts1 = 200°C

u1 = 2654.6KJ/Kg

v1 = 1.08049 m³/Kg

At P2 = 100kPa, v1 = v2

vf = 0.001043m³, vg = 1.6941m³/kg uf = 417.4kj/kg ufg = 2088.2kj/kg

x2 = (v2 - vf)/(vg - vf)

x2 = (1.08049 - 0.001043)/(1.6941 - 0.001043)

x2 = 1.079447/1.693057

x2 = 0.63757

u2 = uf + x2ufg

u2 = 417.4 + 0.63757 * 2088.2

u2 = 417.4 + 1331.374

u2 = 1748.774

Solving for m

m = V1/v1

m = 15L/1.08049

m = 0.015/1.08049

m = 0.01388Kg

So, -Qout = m(u2 - u1) becomes

0.01388(1748.774 - 2654.6)

= 0.01388 * -905.826

= -12.572

-Qout = -12.572

So, Qout = 12.572KJ

The dimensions of the room is 3 * 4 * 5.

The mass and volume of air in the room is given by

Volume = 3 * 4 * 6 = 72m³

Mass = P * V/RT

Where R = Gas Constant = 0.287

T = T1 = 7°C = 273+ 7 = 280K

P = P2 = 100kPa

Mass = (100 * 72)/(0.287 * 280)

Mass = 7200/80.36

Mass = 89.597Kg

The amount of work is defined by

Work = Fan work W * Time t

Work = 120 * 45 minutes

Work = 120 * 45 * 60seconds

Work = 324000J

Work (fan, in) = 324KJ

Taking the air in the room as the system

The energy balance is as follows

∆Energy = E(in) - E(out)

E(in) = Q(out) + W(fan,in)

E(out) = W(out)

∆Energy = ∆U

So, we have

∆U = Q(out) + W(fan,in) - W(out)

∆U + W(out) = Q(out) + W(fan,in)

∆U + W(out) = 12.572 + 324

∆U + W(out) = 336.572

∆U + W(out) = ∆H (Change in heat energy)

This is given by mc(T2 - T1)

Where m = 89.597kg

c = specific heat of air at constant pressure = 1.005

T1 = 7°C

Substituting in these values, we have

336.572 = 89.597 *1.005 (T2 - 7)

=> 336.572 = 90.044985(T2 - 7)

T2 - 7 = 3.74

T2 = 3.74 + 7

T2 = 10.74°C

8 0

4 years ago