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Bingel [31]
3 years ago
6

The Rotokas of Papua New Guinea have twelve letters in their alphabet. The letters are: A, E, G, I, K, O, P, R, S, T, U, and V.

Suppose license plates of five letters utilize only the letters in the Rotoka alphabet. How many license plates of five letters are possible that begin with either G or K, end with T, cannot contain S, and have no letters that repeat?
Mathematics
1 answer:
Mnenie [13.5K]3 years ago
3 0

12 letters in all but less "S" which is not allowed. That leave 11 usable letters, of which 5 distinct letters are used for each plate.

begins with G or K (2 choices). That leaves 10 letters.

Ends with T (1 choice). That least 9 for the middle letters.

Second letter (9 choices)

Third letter (8 choices)

Fourth letter (7 choices)

Total number of licence plates

=product of choices of letters for each position

= 2*9*8*7*1

=1008

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The midpoint of AB is point G

<h2>Explanation:</h2>

The complete question has been attached below. As you can see, we have a line segment which is defined as a part of a line that is bounded by two different points that are at the end of the segment. So here we know that:

  • A is located at point -6.
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Therefore, the midpoint can be calculated as:

M:midpoint \\ \\ \\ M=\frac{A+B}{2} \\ \\ M=\frac{-6+8}{2} \\ \\ M=1

So the midpoint is M=1 that matches point G. Finally:

Conclusion: The midpoint of AB is point G

Learn more:

Midpoint: brainly.com/question/13773601

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Answer:

Concept: Mathematics

When you multiply a number by something to the 10 power of something then you move whatever place of the exponential to the right if its positive and left if it's negative.

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You keep doing the same thing

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Lastly

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