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Diano4ka-milaya [45]
2 years ago
10

He system of equations below has no solution.

Mathematics
1 answer:
vesna_86 [32]2 years ago
8 0

a linear combination can be:

(a + b)*(4x + 15y) = a*12 + b*15

<h3>How to solve the given system of equations:</h3>

Here we have the system of equations:

(2/3)*x + (5/2)*y = 15

4x + 15y = 12

To solve the system of equations, we first need to isolate one of the variables in one of the equations, I will isolate x on the second equation.

4x = 12 - 15y

x = (12 - 15y)/4

Now we can replace that in the other equation:

(2/3)*x + (5/2)*y = 15

(2/3)* (12 - 15y)/4 + (5/2)*y = 15

Now we can solve that for y.

2 - (10/4)*y + (5/2)*y = 15

2 = 15

That is a false equation, then we conclude that the system of linear equations has no solutions.

This means that the two lines are parallel lines, then a linear combination can be:

(a + b)*(4x + 15y) = a*12 + b*15

Where a and b are two real numbers.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

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