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3 years ago

What two-dimensional shape is formed by a cross section of the cone shown from the vertex perpendicular to the base of the cone?

Mathematics

1 answer:

Ber [7]3 years ago

8 0

The correct choice is D!

Hope this helped you out! :)

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The major math strands for a sixth grade curriculum are number sense and operations, algebra, geometry and spatial sense, measur

Radda [10]

Answer:

i didn't learn algebra or geometry or spatial sense when i was in sixth grade

Step-by-step explanation:

3 0

3 years ago

Find the missing probability. P(B)=720,P(A|B)=14 ,P(A∩B)=?

Ivan

Answer:

7/80

Step-by-step explanation:

Given that: P(B) = 7 / 20, P(A|B)= 1 / 4

Bayes theorem is used to mathematically represent the conditional probability of an event A given B. According to Bayes theorem:

$P(A|B)=\frac{P(A \cap B)}{P(B)}$

Where P(B) is the probability of event B occurring, P(A ∩ B) is the probability of event A and event B occurring and P(A|B) is the probability of event A occurring given event B.

$P(A|B)=\frac{P(A \cap B)}{P(B)}\\\\P(A \cap B)=P(A|B)*P(B)\\\\Substituting:\\\\P(A \cap B)=1/4*7/20=7/80\\\\P(A \cap B)=7/80$

6 0

3 years ago

Solve the equation by graphing. 1/3x+ 5 = -2x - 2<br>Please I need the point where the line goes

jenyasd209 [6]

Answer:

Check attachment.

Step-by-step explanation:

I graphed it.

3 0

3 years ago

Match each graph to its equation.

sertanlavr [38]

Answer:

1- A

2- C

3- B

4- D

Step-by-step explanation:

5 0

2 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago