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jenyasd209 [6]
3 years ago
12

What two-dimensional shape is formed by a cross section of the cone shown from the vertex perpendicular to the base of the cone?

Mathematics
1 answer:
Ber [7]3 years ago
8 0

The correct choice is D!

Hope this helped you out! :)

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The equation (x-6)^2/16 + (y+7)^2/4 = 1 represents an ellipse. What are the vertices of the ellipse?
topjm [15]

Answer:

The correct option is C.

Step-by-step explanation:

The given equation is

\frac{(x-6)^2}{16}+\frac{(y+7)^2}{4}= 1

It can be rewritten as

\frac{(x-6)^2}{4^2}+\frac{(y+7)^2}{2^2}= 1         .....(1)

The standard form of an ellipse is

\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}= 1           ....(2)

Where (h,k) is center of the ellipse.

If a>b, then the vertices of the ellipse are (h\pm a, k).

From (1) and (2) we get

h=6,k=-7,a=4,b=2

Since a>b, therefore the vertices of the ellipse are

(h+a, k)=(6+4,-7)\Rightarrow (10,-7)

(h-a, k)=(6-4,-7)\Rightarrow (2,-7)

The vertices of the given ellipse are (10, –7) and (2, –7). Therefore the correct option is C.

5 0
3 years ago
Read 2 more answers
Find all the integer solutions of each system of inequalities.<br> 3-18x &lt; 0<br> 0.2-0.1x &gt; 0
Korolek [52]
3-18x & 0 0.2-0.1x do you have. A picks
5 0
2 years ago
Read 2 more answers
The time needed to complete a final examination in a particular college course is normally distributed with a mean of 80 minutes
mixer [17]

Answer:

0.02275

Step-by-step explanation:

We have been given that the time needed to complete a final examination in a particular college course is normally distributed with a mean of 80 minutes and a standard deviation of 10 minutes. We are asked to find the probability of completing the exam in one hour or less.

We know that 1 hour equals 60 minutes. First of all, we will find the z-score corresponding to 60 minutes.  

z=\frac{x-\mu}{\sigma}

z = z-score,

x = Sample score,

\mu = Mean,

\sigma = Standard deviation.

z=\frac{60-80}{10}

z=\frac{-20}{10}

z=-2

Now, we will use normal distribution table to find area under z-score of -2 as:

P(z< -2)

P(z< -2)=0.02275

Therefore, the probability of completing the exam in one hour or less is 0.02275.

7 0
3 years ago
To test μ for an x distribution that is mound-shaped using sample size n ≥ 30, how do you decide whether to use the normal or st
Luden [163]
Answer:
Use the normal distribution if the population standard deviation is known.
Use the student's t distribution when the population standard deviation is unknown.

Explanation:
A mound-shaped distribution refers to the normal distribution.
A good sample size for testing against the normal distribution should be
n >= 30.
The condition for the sample size is satisfied.
However, we are not given the population standard deviation, therefore it is assumed to be unknown.
Therefore the student's t distribution should be used. 
6 0
3 years ago
What percent of 9775 is 1275
ahrayia [7]
1275 ÷ 9775= 0.1304% or 0.13%

7 0
3 years ago
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