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Ganezh [65]
2 years ago
15

For each of the number lines, write an absolute value equation that has the following solution set. 26 and m

Mathematics
1 answer:
alexira [117]2 years ago
6 0

On a number line, an absolute value equation that has the given solution set is |m - 4| = 2.

<h3>How to write the absolute value equation?</h3>

By critically observing the given question, we can infer and logically deduce that the solution sets for this absolute value equation is given by:

m = {2, 6}

Next, we would calculate the mean of the solution sets as follows:

m₁ = (2 + 6)/2

m₁ = 8/2

m₁ = 4.

Also, we would calculate the difference in the solution sets as follows:

m₂ = (6 - 2)/2

m₂ = 4/2

m₂ = 2.

Mathematically, the absolute value equation is given by:

|m - m₁| - m₂ = 0

|m - 4| - 2 = 0

|m - 4| = 2.

Read more on absolute value equation here: brainly.com/question/27197258

#SPJ1

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Answer:

y = x - 1

Step-by-step explanation:

Find the slope:

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3 years ago
A manufacturer of nails claims that only 4% of its nails are defective. A random sample of 20 nails is selected, and it is found
irakobra [83]

Answer:

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

Step-by-step explanation:

A manufacturer of nails claims that only 4% of its nails are defective.

At the null hypothesis, we test if the proportion is of 4%, that is:

H_0: p = 0.04

At the alternative hypothesis, we test if the proportion is more than 4%, that is:

H_a: p > 0.04

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

4% is tested at the null hypothesis

This means that \mu = 0.04, \sigma = \sqrt{0.04*0.96}

A random sample of 20 nails is selected, and it is found that two of them, 10%, are defective.

This means that n = 20, X = 0.1

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.1 - 0.04}{\frac{\sqrt{0.04*0.96}}{\sqrt{20}}}

z = 1.37

P-value of the test and decision:

Considering an standard significance level of 0.05.

The p-value of the test is the probability of finding a sample proportion above 0.1, which is 1 subtracted by the p-value of z = 1.37.

Looking at the z-table, z = 1.37 has a p-value of 0.9147

1 - 0.9147 = 0.0853

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

7 0
3 years ago
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