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____ [38]
3 years ago
5

Find the 70th term of the following arithmetic sequence. 13, 22, 31, 40,

Mathematics
2 answers:
natali 33 [55]3 years ago
7 0

Answer:

634

Step-by-step explanation:

Nth term of an arithmetic progression is given by:

Tn=a+(n-1)d

Where 'Tn' is the Nth term of A.P. , 'a' is the first term of A.P. , 'n' is the no. of terms and 'd' is the common difference.

22-13=9, 31-22=9, 40-31=9.

So, d=9

a=13

n=70

Put the values in the Formula.

T70=13+(70-1)*9=13+69*9=13+621=634

Lerok [7]3 years ago
4 0
Its 31 just trust me homie;)
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