Go to lesson page Problem If you flip three fair coins, what is the probability that you'll get a head on the first flip, a tail
on the second flip, and another head on the third flip?
1 answer:
The probability of any particular sequence of N flips of a fair coin is 2^(-N).
Your probability of the given sequence of 3 coin flips is
2^-3 = 1/8
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Step-by-step explanation:
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Answer:
n greater than 4
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Base leg (b) = 6
Other leg (a) = 14
Hypotenuse (c) = c
plug this into the equation above and solve for c (taking the square root to solve) so:
142 + 62 = c2
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Hope this helps have a good day. :)