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2 years ago

If you borrow $800 for 10 years at an annual interest rate of 12%, how much will you pay altogether?

Mathematics

2 answers:

Virty [35]2 years ago

8 0

Answer:

$1,760

Step-by-step explanation:

So I'm assuming the interest is simple interest rate which means that the interest applied each year is 12% of the original amount.

So this means that we can find the interest rate from one year by finding 12% of 800, and to do this we convert 12% to a decimal by dividing by 100 to get 0.12 and then use this decimal value to multiply by 800 to get: 0.12 * 800 = 96.

This means annually $96 will be charged in interest. To find how much interest there is after 100 years, simply multiply by 10, to get $96 * 10 = $960.

This is only the interest rate, it's like a fee, you still have to pay back the original amount, so all together you pay: $ borrowed + interest

So we add the interest rate 960 to the amount borrowed 800 to get: 960 + 800 = 1,760

Alex Ar [27]2 years ago

4 0

Answer:

the principal amount is 10000 is the rate of interest is 10 and the number of years is 10 you can calculate the simple interest a is equal to 10000 1 + 0 is equal to 1.6 is equal to 16000 interest is equal to a - b is equal to 6000 - 1000

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3 years ago

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2 years ago

I need the volume for 9,11,and 13

mihalych1998 [28]

Hey there!

<h3>Question 1</h3>

Let's use 3.14 for pi during this. It'll make it a lot easier.

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17.6 ÷ 2 = 8.8

The height of this cone is 23.4 inches.

Plug the values into the equation.

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Next, square 6.8 and divide 23.4 by 3. Also, replace the pi symbol with 3.14.

$3.14 * 77.44 * 7.8$

Multiply the numbers together.

<u>The volume of this cone is approximately 1896.66 cubic inches.</u>

<h3>Question 2</h3>

Finding the volume of a trapezoidal prism can be done by finding the are of the trapezoidal face and multiplying it by the depth.

Formula for finding the area of a trapezoid is $a = \frac{1}{2} h(b_{1} +b_{2} )$

The two bases are 10 and 34, and the height is 24.7 feet. Put these values into the equation.

$a = \frac{1}{2} 24.7(10 +34 )$

Add 10 and 34, then multiply it by 24.7 and 1/2.

a = 543.4

Multiply that value by 19, which is the depth of the figure.

<u>The volume of the prism is 10324.6 cubic feet.</u>

<h3>Question 3</h3>

The formula for volume of a triangular pyramid is v = 1/3ah, with a the area of the base and h the height.

The formula for the area of an equilateral triangle, which is the base, is $a = \frac{\sqrt{3} }{4} s^{2}$

The length of the side is 12, so we can square that to get 144.

Now multiply that by $\frac{\sqrt{3} }{4}$ to get the area of the base.

The area of the base is about 62.35 square meters.

The height of the pyramid is 20 meters. Plug that and the area of the base into the equation.

v = 1/3 x 62.35 x 20

Multiply the numbers together to get the volume.

<u>The volume of the pyramid is approximately 415.67 cubic meters.</u>

Hope this helps!

3 0

3 years ago

Select the correct answer. What is the surface area of the victory podium shown here? Include all surfaces of the podium, includ

Leya [2.2K]

Answer:

Option C is correct.

Step-by-step explanation:

Given the dimension of the surfaces i.e length, width and height of podium. we have to calculate the surface area of the victory podium.

As Surface area of cuboid is 2(LW+WH+HL)

In the given figure, the upper cuboid has dimension

L=2.5 ft. , W=1.5 ft, H=1.5 ft

$\text{Surface area=}2(2.5(1.5)+1.5(1.5)+1.5(2.5))=19.5ft^2$

$\text{Area of bottom face of upper cuboid=}L\timesW=2.5\times1.5=3.75ft^2$

The upper face is occuring twice therefore it must be subtracted to find the area

Dimensions of lower podium are

L=7.5 ft. , W=1.5 ft, H=1.5 ft

$\text{Surface area=}2(7.5(1.5)+1.5(1.5)+1.5(7.5))=49.5ft^2$

Now, Surface area of podium included bottom is

19.5+49.5-3.75=65.25 square feet.

Hence, option C is correct.

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3 years ago

If you borrow $800 for 10 years at an annual interest rate of 12%, how much will you pay altogether?​

If you borrow $800 for 10 years at an annual interest rate of 12%, how much will you pay altogether?