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hammer [34]
3 years ago
15

List the first 9 terms of the sequence defined recursively by Sn = Sn-2. (Sn-1 - 1), with S1 = 2 and

Mathematics
1 answer:
STALIN [3.7K]3 years ago
5 0

Explanation

Given that Sn = Sn-2 . (Sn-1 - 1)

Tn = Sn - Sn-1

Tn = Sn-2 . (Sn-1 - 1) - (Sn-3 . (Sn-2 - 1))

T3 = S1.(S2-1) - (S0.(S1-1)

T3 = 2.(3-1) - 1.(2-1)

T3 = 2(2) - 1(1)

T3 = 4-2

T3 = 3

T4 = S2.(S3-1) - (S1.(S2-1)

T4 =3.(-1) - 1.(2-1)

T4 = 2(2) - 1(1)

T4 = 4-2

T4 = 3

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solniwko [45]

Step-by-step explanation:

Here we are given that , the Value of

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And we need to find the prove that ,

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We know a identity as ,

  • (a-b)^3 = a^3-b^3-3ab(a-b)

On cubing both sides of the given equation,

  • (3x-2y)^3 = 9^3

Simplify and then substitute ,

  • 27x^3-8y^3 -3(3x)(2y)(3x-2y ) = 729

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Hence Proved !

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Step-by-step explanation:

To find y, follow these steps:

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