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ruslelena [56]
2 years ago
7

Solve (6b^2+5)+(8b-20)

Mathematics
1 answer:
Lisa [10]2 years ago
7 0

The sum of the given expression is 6b^2+8b-15

<h3>Sum of expression</h3>

Given the following expression

(6b^2+5)+(8b-20)

We are to take the sum. On expansion;

6b^2+5 + 8b-20

Collect the like terms

6b^2+8b +5 - 20

6b^2+8b-15

Hence the sum of the given expression is 6b^2+8b-15

Learn more on sum of expression here: brainly.com/question/723406

#SPJ1

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2/3 + 5/6 in the simplest form
asambeis [7]
Here is your answer:

2×2=4
3×2=6
+
5×1=5
6×1=6

4+5=9

9÷3=3
6÷3=2

Your answer is...
=3/2
6 0
3 years ago
Which of the following values could the number 500,000 be composed of?
OverLord2011 [107]

50000 tens

5000hundreds

How?

  • 1ten=10

50000 tens:-

\\ \sf\longmapsto 50000(10)=500000

  • 1hundred=100

5000hundreds

\\ \sf\longmapsto 5000(100)=500000

8 0
3 years ago
Read 2 more answers
Find the answer pleaseeee...<br><br>-15/9 + 9/4 = ? <br><br>Please find what the question mark is​
SVEN [57.7K]

Answer:

7/12

Step-by-step explanation:

-15/9+9/4

We need to make them have the same denominator:

9x4= 36 so that is our new denominator

-15x4= -60

9x9=81

(Sorry if i dont make sense)

Now we have -60/36+81/36 which is equal to 21/36.

Now we simplify:

21/36=7/12

3 0
3 years ago
If f(x) = -2x^2 + x–5, what is f(3)?
yan [13]

Answer:

-20

Step-by-step explanation:

Replace X by 3

f(3) = -2(3)^2+ (3)-5 = -20

7 0
3 years ago
what is the probability of seeing a sample mean for 21 observations less or equal to the sample mean that we observed
kramer

Answer:

P(x \le 21) = 0.69146

Step-by-step explanation:

The missing parameters are:

n = 64 --- population

\mu = 20 --- population mean

\sigma = 16 -- population standard deviation

Required

P(x \le 21)

First, calculate the sample standard deviation

\sigma_x = \frac{\sigma}{\sqrt n}

\sigma_x = \frac{16}{\sqrt {64}}

\sigma_x = \frac{16}{8}

\sigma_x = 2

Next, calculate the sample mean \bar_x

\bar x = \mu

So:

\bar x = 20

So, we have:

\sigma_x = 2

\bar x = 20

x = 21

Calculate the z score

x = \frac{x - \mu}{\sigma}

x = \frac{21 - 20}{2}

x = \frac{1}{2}

x = 0.50

So, we have:

P(x \le 21) = P(z \le 0.50)

From the z table

P(z \le 0.50) = 0.69146

So:

P(x \le 21) = 0.69146

4 0
3 years ago
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