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ruslelena [56]
2 years ago
7

Solve (6b^2+5)+(8b-20)

Mathematics
1 answer:
Lisa [10]2 years ago
7 0

The sum of the given expression is 6b^2+8b-15

<h3>Sum of expression</h3>

Given the following expression

(6b^2+5)+(8b-20)

We are to take the sum. On expansion;

6b^2+5 + 8b-20

Collect the like terms

6b^2+8b +5 - 20

6b^2+8b-15

Hence the sum of the given expression is 6b^2+8b-15

Learn more on sum of expression here: brainly.com/question/723406

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I need help with this page
yaroslaw [1]

Remember,

sin = op/hyp

cos = adj/hyp

tan = op/adj

For question 3 it would be B and C, because the adjacent side of angle x is 12, the hypotenuse is 37, and cos = adj/hyp.  Also, the opposite side of angle z is 12, and the hypotenuse is 37, and sin = op/hyp.  So both answers would be 12/37. You would do the same with question 4.

For 5, you would do the same thing.  It would be D because you can only take the sin of angle 24, and x is a side.  the opposite of 24 is x and the hypotenuse is 11, so sin 24 would be x/11. It is the same for problem 6.

6 0
2 years ago
Solve for x 5 x − 1 = 6 x − 9
Oksi-84 [34.3K]

Answer:

The value of x in this equation is 8.

Step-by-step explanation:

5x - 1 = 6x - 9

Subtract 6x on both sides.

-x - 1 = -9

Add 1 to both sides.

-x = -8

Divide by -1 on both sides.

x = 8

8 0
3 years ago
There are eight volunteers at the election. The goal for the evening is to raise $952. If each volunteer raises the same amount,
Stells [14]
Each volunteer has to raise 119 dollars
4 0
3 years ago
Read 2 more answers
K=am+3mx solve for m
Otrada [13]
Assuming the variables are constants, you isolate m. So move am to the left. K-am=emx. Now divide ex. This gives you, m=(K-am/ex)
7 0
3 years ago
Find the range of the following piecewise function.
mash [69]

Answer:

\huge\boxed{[-5;\ -2)\ \cup\ [3;\ 13)}

Step-by-step explanation:

The following piecewise functions are linear functions. The graph of any of them is a line segment.

We just need to calculate the value of the function at each end specified in the brace.

y=3x-2\ \text{if}\ -1\leq x

Substitute x =-1 and x = 0:

x=-1\\y=3(-1)-2=-3-2=-5\\\\x=0\\y=3(0)-2=0-2=-2

Range of this piece is [-5; -2)

y=2x+3\ \text{if}\ 0\leq x

Substitute x =0and x = 5:

x=0\\y=2(0)+3=0+3=3\\\\x=5\\y=2(5)+3=10+3=13

Range of this piece is [3; 13)

Therefore the range of the following piecewise function is:

[-5;\ -2)\ \cup\ [3;\ 13)

Look at the picture.

6 0
3 years ago
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