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2 years ago

Solve (6b^2+5)+(8b-20)

Mathematics

1 answer:

Lisa [10]2 years ago

7 0

The sum of the given expression is 6b^2+8b-15

<h3>Sum of expression</h3>

Given the following expression

(6b^2+5)+(8b-20)

We are to take the sum. On expansion;

6b^2+5 + 8b-20

Collect the like terms

6b^2+8b +5 - 20

6b^2+8b-15

Hence the sum of the given expression is 6b^2+8b-15

Learn more on sum of expression here: brainly.com/question/723406

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2/3 + 5/6 in the simplest form

asambeis [7]

Here is your answer:

2×2=4
3×2=6
+
5×1=5
6×1=6

4+5=9

9÷3=3
6÷3=2

Your answer is...
=3/2

6 0

3 years ago

Which of the following values could the number 500,000 be composed of?

OverLord2011 [107]

50000 tens

5000hundreds

How?

1ten=10

50000 tens:-

$\\ \sf\longmapsto 50000(10)=500000$

1hundred=100

5000hundreds

$\\ \sf\longmapsto 5000(100)=500000$

8 0

3 years ago

Read 2 more answers

Find the answer pleaseeee...<br><br>-15/9 + 9/4 = ? <br><br>Please find what the question mark is

SVEN [57.7K]

Answer:

7/12

Step-by-step explanation:

-15/9+9/4

We need to make them have the same denominator:

9x4= 36 so that is our new denominator

-15x4= -60

9x9=81

(Sorry if i dont make sense)

Now we have -60/36+81/36 which is equal to 21/36.

Now we simplify:

21/36=7/12

3 0

3 years ago

If f(x) = -2x^2 + x–5, what is f(3)?

yan [13]

Answer:

-20

Step-by-step explanation:

Replace X by 3

f(3) = -2(3)^2+ (3)-5 = -20

7 0

3 years ago

what is the probability of seeing a sample mean for 21 observations less or equal to the sample mean that we observed

kramer

Answer:

$P(x \le 21) = 0.69146$

Step-by-step explanation:

The missing parameters are:

$n = 64$ --- population

$\mu = 20$ --- population mean

$\sigma = 16$ -- population standard deviation

Required

$P(x \le 21)$

First, calculate the sample standard deviation

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{16}{\sqrt {64}}$

$\sigma_x = \frac{16}{8}$

$\sigma_x = 2$

Next, calculate the sample mean $\bar_x$

$\bar x = \mu$

So:

$\bar x = 20$

So, we have:

$\sigma_x = 2$

$\bar x = 20$

$x = 21$

Calculate the z score

$x = \frac{x - \mu}{\sigma}$

$x = \frac{21 - 20}{2}$

$x = \frac{1}{2}$

$x = 0.50$

So, we have:

$P(x \le 21) = P(z \le 0.50)$

From the z table

$P(z \le 0.50) = 0.69146$

So:

$P(x \le 21) = 0.69146$

4 0

3 years ago