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LenKa [72]
2 years ago
10

Help me solve this question!

Mathematics
1 answer:
MakcuM [25]2 years ago
5 0

Answer:

1st quartile is 136

The second quartile is also the median 142

The third quartile is 162

The interquartile range is the difference between the 3rd and first quartile or 26

Step-by-step explanation:

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What are the solutions for x when y is equal to 0 in the following quadratic
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<u>Answer:</u>

The correct answer option is E) No solution.

<u>Step-by-step explanation:</u>

We are given the following quadratic equation which we are to solve for x when the value of y is 0:

y = x ^2+ 6x +12

x ^2+ 6x +12=0

Using the quadratic formula since there are no factors:

x=\frac{-b \pm \sqrt{b^2-4ac }}{2a}

Substituting the values in the formula to get:

x=\frac{-6 \pm \sqrt{6^2-4(1)(12) }}{2(1)}

x=-3+\sqrt{3}i or x=-3-\sqrt{3}i

There are no real number solutions to this quadratic equation.

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