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Leviafan [203]
3 years ago
15

5 screen shots plz help plz will choose brianyest and will give 19 pts

Mathematics
1 answer:
Taya2010 [7]3 years ago
7 0
Tigers! Have a great day!
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James said that he would need 25 red beads to make
o-na [289]

Answer:Elena uses 12 red beads to make 4 bracelets. How many red beads will Elena need to make 12 bracelets? How many red beads will Elena need to make 20 bracelets? You can make a table showing the number of bracelets that can be made with different numbers of red beads. The pairs of numbers in each column show the ratio ofred beads to bracelets. Notice the ratios are all equivalent.

Number of Red Beads 3 6 12 24 36 48 60 72 Number of Bracelets 1 2 4 8 12 16 20 24  

The table shows Elena will need 36 red beads to make 12 bracelets. Elena will need 60 red beads to make 20 bracelets. James said that he would need 25 red beads to make 75 bracelets. Is he correct? How did he get that answer?

Step-by-step explanation:

5 0
3 years ago
The price of a product increased by $75, which was a 15% increase. What was the product's original price?
Leni [432]
75 x 15= 1,125
1,125/100=11.25
75-11.25= 63.75


6 0
3 years ago
two boxes of identical birthday candles are pictured: a 2 ounces box and 6- ounces box. There is 96 candles in the large box. Ho
Sladkaya [172]

Answer:  There are 32 candles in the small box.

Step-by-step explanation:

Since we have given that

Size of small box= 2 ounces

Size of large box = 6 ounces

Number of candles in large box = 96,

We need to find the number of candles in the small box ,

As there is direct variation between the small box and large box ,

let the number of candles in the small box be x

So,

\frac{96}{6}=\frac{x}{2}\\\\16=\frac{x}{2}\\\\16\times 2=x\\\\32=x

so, there are 32 candles in the small box.

7 0
3 years ago
Find the midpoint of the segment with the following endpoints.<br> (8,5) and (0, -1)
Karo-lina-s [1.5K]

Answer:

(4,2)

Step-by-step explanation:

Midpoint =\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(8,\:5\right),\:\\\left(x_2,\:y_2\right)=\left(0,\:-1\right)\\\\=\left(\frac{0+8}{2},\:\frac{-1+5}{2}\right)\\\\= (\frac{8}{2} , \frac{4}{2} )\\\\Simplify\\=\left(4,\:2\right)

6 0
3 years ago
Marie has a small copy of Rene Magritte's famous painting, The Schoolmaster. Her copy has dimensions 2 inches by 1.5 inches. The
Alex73 [517]
A. Find the dimensions of the original painting.

 

Since the scale is 1 in : 40 cm

2 in ( 40 cm / 1 in) = 80 cm

1.5 in ( 40 cm / 1 in) = 60 cm

80 cm by 60 cm

 

B. Find the area of the original painting.

<span>A =  80 cm x 60 cm = 4800 sq cm</span>

 

C. Since 1 inch is 2.54 cm, find the dimensions of the original painting in inches.

80 cm ( 1 in / 2.54 cm) = 31.5 in

60 cm ( 1 in / 2.54 cm) = 23.6 in

 

D, Find the area of the original painting in square inches.

A = 31.5 in x 23.6 in = 743.4 sq in

<span> </span>

5 0
3 years ago
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