Answer:
The radius of the inflated spherical balloon is 45 millimeters.
Step-by-step explanation:
Volume of the spherical water balloon = 121,500 pi cubic millimeters
Let the radius of the balloon = r
Now, Volume of a Sphere = 
⇒
On solving for the value of r, we get:
![r^{3} = \frac{121,500\times 3}{4} = 91125\\ \implies r = \sqrt[3]{91125}](https://tex.z-dn.net/?f=r%5E%7B3%7D%20%20%3D%20%5Cfrac%7B121%2C500%5Ctimes%203%7D%7B4%7D%20%20%20%3D%2091125%5C%5C%20%5Cimplies%20%20r%20%20%3D%20%5Csqrt%5B3%5D%7B91125%7D)
or, r = 45 millimeter
Hence, the radius of the inflated spherical balloon is 45 millimeters.
Answer:
i think BC = 8.5
Step-by-step explanation:
19-(2+6.5+2)
19-10.5
8.5
250 cm³
the volume of a cuboid(V) = length × breadth × height
V = 5 × 10 × 25 1250 cm³
note 1 litre = 1000 cm³
empty space = 1250 - 1000 =250 cm³
A) The complement of an angle is the other angle that can be added to the original to add up to 90 degrees. The complement of <ABD would be 90-36
=54
b) The supplement of an angle is whatever number can be added to the original to add up to 180 degrees. The supplement of <ABD would be 180-36
=144
You first combine like terms.
6.51 - 9.32 + h = 1.02
-2.81 + h = 1.02
To isolate the variable you need to add 2.81 to both sides.
h = 3.83
And that is your final answer.
I hope this helps love! :)
