There are 120 ways in which 5 riders and 5 horses can be arranged.
We have,
5 riders and 5 horses,
Now,
We know that,
Now,
Using the arrangement formula of Permutation,
i.e.
The total number of ways
,
So,
For n = 5,
And,
r = 5
As we have,
n = r,
So,
Now,
Using the above-mentioned formula of arrangement,
i.e.
The total number of ways
,
Now,
Substituting values,
We get,

We get,
The total number of ways of arrangement = 5! = 5 × 4 × 3 × 2 × 1 = 120,
So,
There are 120 ways to arrange horses for riders.
Hence we can say that there are 120 ways in which 5 riders and 5 horses can be arranged.
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Answer:
Step-by-step explanation:
y = 6
x = 9
x+7y
9 + 7(6)
9+ 42
51
Answer:
trapizoids
Step-by-step explanation:
Evaluate:
First you calculate the exponent:

27 + 1 <span>⋅ 9 + 12
</span>Then you multiply and divide left to right: 1 <span>⋅ 9 = 9
27+ 9 + 12
Then add and subtract:
27 + 9 + 12 = 48
So the answer to this is 48.
Hope I helped :)
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