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3 years ago

3/7x + 5= 8 solve the equation

Mathematics

2 answers:

BigorU [14]3 years ago

8 0

Answer:

x=7

Step-by-step explanation:

3/7(7)+5=8

DanielleElmas [232]3 years ago

6 0

Answer:

Step-by-step explanation:

3/7x+5=8

Subtract 5 from each side of the equation.

3/7x=3

Divide each side by 3/7

X=3/ (3/7)

To divide by a fraction, we Can flip the fraction, (7/3) and multiply.

X= 3(7/3)

X=21/3

X=7

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Use the laws of logarithms and the values given below to evaluate the logarithmic expression (picture provided)

nydimaria [60]

Answer: Option a.

Step-by-step explanation:

To solve the given exercise, you must keep on mind the law of logarithms shown below:

$log(a)-log(b)=log(\frac{a}{b})$

Therefore, by applying the law , you can rewrite the expression given, as following:

$log(\frac{5}{7})=log(5)-log(7)$

You know that:

$log5=0.6990\\log7=0.8451$

Then, when you substitute values, you obtain:

$0.6990-0.8451=-0.1461$

4 0

3 years ago

Read 2 more answers

you are buying fruit to make fruit baskets apples comes in bags of 20 oranges come in bags of 16 and bananas coming back to 32.

olasank [31]

The answer to the question

6 0

3 years ago

Select the correct answer from the drop-down menu.

expeople1 [14]

Answer:

Step-by-step explanation: x^(105)-x^(3m)=0

5 0

3 years ago

Find the mistake and correct it

Murljashka [212]

Answer:

i believe its the second part thats wrong

Step-by-step explanation:

1 Distribute

−5(−2+10)=20

10−50=20

2 Add 50 to both sides of the equation

10−50=20

10−50+50=20+50

3 Simplify

Add the numbers

10x−50+50=20+50

10=20+50

Add the numbers

10x =20 + 50

10x=10

4 Divide both sides of the equation by the same term

10x = 70

10x 70

---- = ----

10 10

5 Simplify

Cancel terms that are in both the numerator and denominator

10x 70

---- = ----

10 10

x = ----

x=7

Solution

= 7

hopes it helps and list brain list plz

6 0

2 years ago

If a person tosses a coin 23 times, how many ways can he get 11 heads

EastWind [94]

Tossing a coin is a binomial experiment.

Now lets say there are 'n' repeated trials to get heads. Each of the trials can result in either a head or a tail.

All of these trials are independent since the result of one trial does not affect the result of the next trial.

Now, for 'n' repeated trials the total number of successes is given by

$_{r}^{n}\textrm{C}$

where 'r' denotes the number of successful results.

In our case $n=23$ and $r=11$ ,

Substituting the values we get,

$_{11}^{23}\textrm{C}=\frac{23!}{11!\times 12!}$

$\frac{23!}{11!\times 12!}=1352078$

Therefore, there are 1352078 ways to get heads if a person tosses a coin 23 times.

3 0

3 years ago