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rewona [7]
2 years ago
5

Jenna has a piece of paper that is 84 square inches in area. it is 10 1/2 inches long. what is the length of the piece of paper

in square inches

Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
6 0
I hope this helps you

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Brums [2.3K]

Answer:

196

Step-by-step explanation:

70% multiply by 4/5(80%) which is 56%

56% times 350

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What is the median for the set of data 3.5 1 3 4​
yawa3891 [41]

Answer:

3.5

Step-by-step explanation:

Test Scores

1, 1, 2, 3, 3, 4, 4, 5, 5, 5

median(middle #)

(3+4)/2 = 7/2 = 3.5

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Round 919827 to the nearst thousand
blondinia [14]
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A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow
Mrrafil [7]

Answer:

\displaystyle \frac{54}{5405}.

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

\displaystyle \left(50\atop 5\right) = 2,118,760.

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

\displaystyle \left( 28\atop 2\right) = 378.

Number of ways to choose 3 green candies out of a batch of 8:

\displaystyle \left(8\atop 3\right)=56.

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168.

The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:

\displaystyle \frac{21,168}{2,118,760} = \frac{54}{5405}.

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