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2 years ago

If a family has 6 children, in how many ways could the parents have 3 boys and 3 girls?

Mathematics

1 answer:

Jlenok [28]2 years ago

4 0

The parents could have 3 boys and 3 girls in 400 ways

<h3>How to determine the number of ways?</h3>

The given parameters are

Children, n = 6

Boys, r = 3

Girls, r =3

The number of combination is:

$Ways = ^nC_{r1} *^nC_{r2}$

So, we have:

$Ways = ^6C_3 *^6C_3$

Apply the combination formula

$Ways = \frac{6!}{3!3!} *\frac{6!}{3!3!}$

This gives

Ways = 400

Hence, the parents could have 3 boys and 3 girls in 400 ways

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Answer:

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Step-by-step explanation:

45.8÷4=11.45 each.

so.if 45.8 is equal to 100%

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11.45×100÷45.8

1145÷45.8 = 25%

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3 years ago

It is estimated that 7% of people in the USA have diabetes. A certain screen in test is a 74.7% accurate for people who do have

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3 years ago

A sample of 66 obese adults was put on a low-carb diet for a year. The average weight loss was 11 pounds and the standard deviat

Illusion [34]

Answer:

The 99% lower confidence bound for the true average weight loss is 3.98 pounds.

This means that we can be 99% sure that the mean weight loss for all obese adults on a low-carb diet is positive.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

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The 99% lower confidence bound for the true average weight loss is 3.98 pounds.

This means that we can be 99% sure that the mean weight loss for all obese adults on a low-carb diet is positive.

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3 years ago

Read 2 more answers

(x-9)(x+2) <br> see if u can find it

ycow [4]

Answer:

x^2 -7x-18

Step-by-step explanation:

(x-9)(x+2)

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first x*x = x^2

outer 2x

inner -9x

last -9*2 =-18

Add together

x^2 +2x-9x-18

Combine like terms

x^2 -7x-18

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3 years ago

Stacey collects baseball cards and recently acquired the rookie cards of a pitcher and a catcher who are being inducted into the

Simora [160]

Answer:

The combined value of the two cards is $V(x)=82(1.03)^x$ .

Step-by-step explanation:

The exponential growth function is defined as

$P(x)=P_0(1+r)^x$

Where, P₀ is initial value, r is growth rate and x is number of years.

The initial value of pitcher's card is $44 and the value of card is expected to increase by 3% per year. The value of pitcher's card after x years is

$F(x)=44(1+0.03)^x$

$F(x)=44(1.03)^x$

The initial value of catcher's card is $38 and the value of card is expected to increase by 3% per year. The value of catcher's card after x years is

$G(x)=38(1+0.03)^x$

$G(x)=38(1.03)^x$

The combined value of two cards is defined as

$V(x)=F(x)+G(x)$

$V(x)=44(1.03)^x+38(1.03)^x$

$V(x)=(44+38)(1.03)^x$

$V(x)=82(1.03)^x$

Therefore, the combined value of the two cards is $V(x)=82(1.03)^x$ .

4 0

4 years ago