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Gnesinka [82]
2 years ago
13

In the student council elections, five students are running for president, two are running for vice president, two are running f

or treasurer and three are running for secretary. How many different possible student council teams could be elected from these students?
​
Mathematics
1 answer:
ki77a [65]2 years ago
6 0

Using the Fundamental Counting Theorem, it is found that 60 different possible student council teams could be elected from these students.

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with n_1, n_2, \cdots, n_n ways to be done, each thing independent of the other, the number of ways they can be done is:

N = n_1 \times n_2 \times \cdots \times n_n

Considering the number of options for president, vice president, treasurer and secretary the parameters are:

n1 = 5, n2 = 2, n3 = 2, n4 = 3.

Hence the number of different teams is:

N = 5 x 2 x 2 x 3 = 60.

More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

#SPJ1

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