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skad [1K]
3 years ago
7

All the fudge machines at a chocolate factory work at the same rate. Six machines working simultaneously can complete a big orde

r in 22 hours.
a
How many hours would it take to fill the order if the number of working machines decreased by factor of 2?
Mathematics
1 answer:
madreJ [45]3 years ago
6 0

Answer:

11 hours

Step-by-step explanation:

The number of machines working in the factory = 6 machines

Decreasing it by a factor of 2 =

6 ÷ 2 = 3 machines.

Hence:

If 6 machines complete a big order = 22 hours

3 machines = x hours

Cross Multiply

6 machines × x hours = 22 hours × 3 machines

x hours = 22 hours × 3/6

= 66/6

x = 11 hours

Therefoee, it would take 11 hours to fill the order if the number of working machines decreased by factor of 2.

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Step-by-step explanation:

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Answer:

Following are the solution to this question:

Step-by-step explanation:

They provide various boxes or various objects.  It also wants objects to be distributed into containers, so no container is empty.  All we select k objects of r to keep no boxes empty, which (r C k) could be done.  All such k artifacts can be placed in k containers, each of them in k! Forms. There will be remaining (r-k) objects. All can be put in any of k boxes.  Therefore, these (r-k) objects could in the k^{(r-k)} manner are organized.  Consequently, both possible ways to do this are

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Consequently, the number of ways that r objects in k different boxes can be arranged to make no book empty is every possible one

= \frac{r!k^{r-k}}{(r-k)!}

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With a short time remaining in the day, a delivery driver has time to make deliveries at 5 locations among the 9 locations remai
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Answer:

15,120

Step-by-step explanation:

The computation of the number of different routes are possible is shown below:

Since there are 5 locations for deliveries among the 9 locations that left

So, the number of routes that could be possible is

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