Answer:
Wireless USB 2.0
Explanation:
USB ports are available in all modern notebook computers. This makes the wireless USB 2.0 adapter a capable option to solve the network issue.
Wireless USB 2.0 can send 480Mbit/s and 110Mbit/s at a 3meters and 10 meters respectively, it frequency ranges from 3.1GHz to 10.6GHz.
In cases where the internal wireless card is faulty or the computer does not come with a wireless chip inside, the Wireless USB 2.0 is the right option for you to be able to connect over a network efficiently.
Answer:
B and C
Explanation:
xPos and yPos determine the center of the circle, and rad determines the radius of the circle drawn.
It cannot be A because it starts drawing a circle with the center of (4, 1). None of the circles ahve a center at (4, 1). It is B because while it does start at (4, 1), the repeat function adds one to the y and radius. While ti repeats 3 times it ends up drawing all 3 circles. C also works because it starts by drawing the biggest circle and then subtracting the values to make the other two. It cannot be D because in the repeat function it subtracts from the y value and radius too early, it doesn't draw the biggest circle.
Cisco Packet Tracer is tool used for network simulation and visualization program.
The two methods can be used to access and modify an existing program that is running on an IoT device in Cisco packet trace are the following:
1. Click on the device then select the Programming tab.
2. Go to the registration server and login. Then select the Editor tab.
Answer:
See the code below and the algorithm explanation on the figure.
Explanation:
The explanation in order to get the answer is given on the figure below.
Solving this problem with C. The program is given below:
#include <stdio.h>
int main(void) {
int n, Even=0, Odd=0, Zeros=0;
for (;;) {
printf("\nEnter the value the value that you want to check(remember just integers): ");
//IF we input a non-numeric character the code end;
if (scanf("%d", &n) != 1) break;
if (n == 0) {
Zeros++;
}
else {
if (n % 2) {
Even++;
}
else {
Odd++;
}
}
}
printf("for this case we have %d even, %d odd, and %d zero values.", Even, Odd, Zeros);
return 0;
}
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The correct answer to this question is c)field.
As we know that the feature of an entity is represented by its attribute in the database table. A database table is a set of records of different fields. Each field represents a row in a database table. Each field can contain a set of attributes related to an entity such as a paint color.
So the price of paint will be in its own field. Because there are different colors in the database table. Each color has its own record in form of a field. As you know that each field is a row in the database table. So, each row has the price of a paint color.
Other options are not correct because:
The table contains a list of fields and each field contains its own paint price. The format and file is something different and does not have any relation with the question scenario.
