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dangina [55]
3 years ago
15

You have a notebook computer and wish to connect to an IEEE 802.11ac wireless network. The computer does not have a built-in WLA

N card or a PC card interface. You do not want any peripherals connected to the notebook that use wires and do not want to disassemble the computer. Which wireless adapter would be the best solution?A. Wireless PCI
B. Wireless PCMCIA
C. Wireless Full Mini-PCIe
D. Wireless USB 2.0
Computers and Technology
1 answer:
BARSIC [14]3 years ago
5 0

Answer:

Wireless USB 2.0

Explanation:

USB ports are available in all modern notebook computers. This makes the wireless USB 2.0 adapter a capable option to solve the network issue.

Wireless USB 2.0 can send 480Mbit/s and 110Mbit/s at a 3meters and 10 meters respectively, it frequency ranges from 3.1GHz to 10.6GHz.

In cases where the internal wireless card is faulty or the computer does not come with a wireless chip inside, the Wireless USB 2.0 is the right option for you to be able to connect over a network efficiently.

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Use the drop-down menus to complete the statements about using column breaks in word 2016
Ugo [173]

Answer: layout, section, number, more options

Explanation:

Just did it on edge 2020

4 0
3 years ago
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Write the following function without using the C++ string class or any functions in the standard library, including strlen(). Yo
dolphi86 [110]

Answer:

The function in C++ is as follows

int chkInd(string str1, string str2){    

int lenstr1=0;

while(str1[lenstr1] != '\0'){  lenstr1++;  }

int index = 0; int retIndex=0;

for(int i=lenstr1-1;i>=0; i--){

   while (str2[index] != '\0'){

       if (str1[i] == str2[index]){

           retIndex=1;

           break;         }

       else{   retIndex=0;      }

  index++;    }

  if (retIndex == 0){   return i;   }else{return -1;}}

}

Explanation:

This defines the function

int chkInd(string str1, string str2){    

First, the length of str1 is initialized to 0

int lenstr1=0;

The following loop then calculates the length of str1

while(str1[lenstr1] != '\0'){  lenstr1++;  }

This initializes the current index and the returned index to 0

int index = 0; int retIndex=0;

This iterates through str1

for(int i=lenstr1-1;i>=0; i--){

This loop is repeated while there are characters in str2

   while (str2[index] != '\0'){

If current element of str2 and str1 are the same

       if (str1[i] == str2[index]){

Set the returned index to 1

           retIndex=1;

Then exit the loop

           break;         }

If otherwise, set the returned index to 0

       else{   retIndex=0;      }

Increase index by 1

  index++;    }

This returns the calculated returned index; if no matching is found, it returns -1

  if (retIndex == 0){   return i;   }else{return -1;}}

}

4 0
3 years ago
Write a function wordcount() that takes the name of a text file as input and prints the number of occurrences of every word in t
artcher [175]

Answer:

Explanation:

The following Python program uses a combination of dictionary, list, regex, and loops to accomplish what was requested. The function takes a file name as input, reads the file, and saves the individual words in a list. Then it loops through the list, adding each word into a dictionary with the number of times it appears. If the word is already in the dictionary it adds 1 to its count value. The program was tested with a file named great_expectations.txt and the output can be seen below.

import re

def wordCount(fileName):

   file = open(fileName, 'r')

   wordList = file.read().lower()

   wordList = re.split('\s', wordList)

   wordDict = {}

   for word in wordList:

       if word in wordDict:

           wordDict[word] = wordDict.get(word) + 1

       else:

           wordDict[word] = 1

   print(wordDict)

wordCount('great_expectations.txt')

4 0
3 years ago
Write a program that reads a series of strings andprints only those strings beginning with the letter "b."
coldgirl [10]

Answer:

#include <iostream>

using namespace std;

int main()

{

char str[100][20];

int n;

cout<<"Strings you want to enter"<<endl;

cin>>n;

cout<<"enter n strings"<<endl;

for(int i=0;i<n;i++)

cin>>str[i];

for(int i=0;i<n;i++)

{

if((int)str[i][0]==98) //ascii value b is 98

cout<<str[i]<<endl;

}

return 0;

}

Explanation:

The above written code is for printing the strings which starts with the letter b.

To check if the string starts with a letter b we are checking the ascii value 98 which corresponds to b and then printing those strings.

6 0
3 years ago
Define a pointer variable named daco that can be used for objects of the class Banana.
ozzi

Answer:

c)Banana * daco;

Explanation:

To declare an variable pointer we use * symbol after writing it's type.For example int *.Then we write the name of the variable since the name of the variable is daco.The class is a user defined data type so instead of writing any data type we will write class name then the * then name of the variable.

Banana * daco; which matches the option c Banana* daco;

4 0
3 years ago
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