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GuDViN [60]
2 years ago
13

Which load balancing method is supported in equal cost multipath (ECMP) load balancing when SD-WAN is enabled

Engineering
1 answer:
Dominik [7]2 years ago
8 0

Volume load balancing method is supported in equal cost multipath (ECMP) load balancing when SD-WAN is enabled.

<h3>What is load balancing method?</h3>

Load balancing means are regarded as a form of an algorithms or method that is used to rightly share an incoming server request or traffic in the midst or among servers that is from the server pool.

Note that Volume load balancing method is supported in equal cost multipath (ECMP) load balancing when SD-WAN is enabled as that is its role.

Learn more about Volume load balancing from

brainly.com/question/28021339

#SPJ1

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Helium gas is compressed from 90 kPa and 30oC to 450 kPa in a reversible, adiabatic process. Determine the final temperature and
ra1l [238]

Answer:

T2 ( final temperature ) = 576.9 K

a) 853.4 kJ/kg

b) 1422.3 kJ / kg

Explanation:

given data :

pressure ( P1 ) = 90 kPa

Temperature ( T1 ) = 30°c + 273 = 303 k

P2 = 450 kPa

Determine final temperature for an Isentropic  process

T2 = T1 (\frac{p2}{p1} )^{(k-1)/k}  ----------- ( 1 )

T2 = 303 ( \frac{450}{90})^{(1.667- 1)/1.667} =  576.9K

Work done in a piston-cylinder device can be calculated using this formula

w_{in} = c_{v} ( T2 - T1 )    ------- ( 2 )

where : cv = 3.1156 kJ/kg.k  for helium gas

             T2 = 576.9K ,    T1 = 303 K

substitute given values Back to equation 2

w_{in}  = 853.4 kJ/kg

work done in a steady flow compressor can be calculated using this

w_{in} = c_{p} ( T2 - T1 )

where : cp ( constant pressure of helium gas )  = 5.1926 kJ/kg.K

             T2 = 576.9 k , T1 = 303 K

substitute values back to equation 3

w_{in} = 1422.3 kJ / kg

4 0
3 years ago
Two added to four times a number, minus 3 times the number, equals 5.
vladimir1956 [14]
<h2>Answer:</h2>

<u>x= 3</u>.

<h2>Explanation:</h2>

<em>What is presented in this problem is basically an equation in verbal form.</em>

<em />

<h3>1. Write the equation.</h3>

2+4x-3x=5

<h3>2. Solve for x.</h3>

2+4x-3x=5\\ \\2+x=5\\ \\x=5-2\\ \\x=3

<h3>3. Express the result.</h3>

x= 3.

8 0
2 years ago
Integrate <br>∫cos²x sinx dx<br>​
Marianna [84]

Answer:

-⅓ cos³ x + C

Explanation:

∫ cos² x sin x dx

If u = cos x, then du = -sin dx.

∫ -u² du

Integrate using power rule:

-⅓ u³ + C

Substitute back:

-⅓ cos³ x + C

3 0
4 years ago
Why does the compression-refrigeration cycle have a high-pressure side and a low-pressure side?
Cloud [144]

Answer: D

Explanation:

8 0
3 years ago
X cotx expansion using maclaurins theorem.
Lemur [1.5K]

It is to be noted that it is impossible to find the Maclaurin Expansion for F(x) = cotx.

<h3>What is Maclaurin Expansion?</h3>

The Maclaurin Expansion is a Taylor series that has been expanded around the reference point zero and has the formula f(x)=f(0)+f′. (0) 1! x+f″ (0) 2! x2+⋯+f[n](0)n!

<h3>What is the explanation for the above?</h3>

as indicated above, the Maclaurin infinite series expansion is given as:

F(x)=f(0)+f′. (0) 1! x+f″ (0) 2! x2+⋯+f[n](0)n!

If F(0) = Cot 0

F(0) = ∝ = 1/0

This is not definitive,

Hence, it is impossible to find the Maclaurin infinite series expansion for F(x) = cotx.

Learn more about Maclaurin Expansion at;
brainly.com/question/7846182
#SPJ1

4 0
2 years ago
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