All categories

2 years ago

43. Consider the equation 4(x-8)+y=9(x-2)

Mathematics

1 answer:

xxMikexx [17]2 years ago

5 0

The expression of the equation 4(x - 8) + y = 9(x - 2) in slope intercept form is; y = 5x + 14

<h3>How to write an equation in Slope Intercept form?</h3>

We want to express 4(x - 8) + y = 9(x - 2) in slope intercept form of y = mx + b.

Let us expand the equation to get;

4x - 32 + y = 9x - 18

Isolate y to get;

y = 9x - 4x - 18 + 32

y = 5x + 14

Thus;

Slope = 5

y - intercept = 14

x - intercept = -2.8

Read more about Slope Intercept Form at; brainly.com/question/1884491

#SPJ1

You might be interested in

The speed of light in cold air is how many times the speed of sound in cold air?

Tju [1.3M]

Answer: B I think

Step-by-step explanation: hope it helps

5 0

2 years ago

Mariana runs at a rate of 300 meters how far does she run in 8 minutes

IgorC [24]

Answer:

well if this is by 300meters in one minutes then it would be 2400 meters

7 0

3 years ago

The probability that any postcard posted in Portugal on Monday is delivered to the UK within a week is 0.62.

sashaice [31]

Answer:

You can expect at least 9 of her postcards to arrive within a week

To find that, we multiply the number of postcards by the probability

15 x 0.62 = 9.3

Hope this helps

Good Luck

5 0

3 years ago

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

4 0

3 years ago

Increase 12 1/2cm by 25mm

Rzqust [24]

12.5 cm = 125 mm + 25 mm = 150 mm the as

7 0

3 years ago