Answer:
multiply by the power of ten,
Step-by-step explanation:
3x - 4y = 8
y = mx + b ; m is the slope ; b is the y-intercept
-4y = -3x + 8
y = -3x/-4 + 8/-4
<u>y = 3/4 x - 2</u>
Need to check if the given choices have the same slope.
3x + 4y = -8
4y = -3x - 8
y = -3/4 x - 8/4 = -3/4 x - 2
6x - 8y = 12
-8y = -6x + 12
y = -6/-8 x + 12/-8
y = 3/4 x - 1 1/2
9x - 12y = 24 This equation would cause a consistent-dependent system
-12y = -9x + 24
y = -9/-12 x + 24/-12
<u>y = 3/4 x - 2</u>
16x + 12y = -10
12y = -16x - 10
y = -16/12 x - 10/12
y = -1 1/3 x - 5/6
The correct answer is:
<span>
The graph shifts 5 units right
Explanation:
Below is the graph attached of both the equations:
Red line: Represents f(x) = </span><span>2x + 2.
Blue line: Represents g(x) = 2x - 3.
As you can see in the graph that g(x) is shifted 5 units right to f(x).
If you move towards right by 1 unit, you have to subtract 1 from f(x) until you reach g(x) like:
2x + 2 - 1 = 2x + 1 (1 unit)
</span>2x + 1 - 1 = 2x (1 unit)
2x - 1 = 2x - 1 (1 unit)
2x - 1 -1 = 2x - 2 (1 unit)
2x -2 - 1 = 2x -3 (1 unit)
Total 5 units.
Hence the correct answer is
t<span>
he graph shifts 5 units right.</span>
<span> sorry it's such a long answer 111.278928823</span>
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Solve the equation:
![\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cdfrac%7B8%7D%7Bx-5%7D-%5Cdfrac%7B9%7D%7Bx-4%7D%3D%5Cdfrac%7B5%7D%7Bx%5E2-9x%2B20%7D%5Cqquad%5Cqquad%28x%5Cne%205~and~x%5Cne%204%29%7D)
Reduce the fractions at the left side so that they have the same denominator:
![\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\ \mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\ \mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\ \mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cdfrac%7B8%28x-4%29%7D%7B%28x-5%29%28x-4%29%7D-%5Cdfrac%7B9%28x-5%29%7D%7B%28x-4%29%28x-5%29%7D%3D%5Cdfrac%7B5%7D%7Bx%5E2-9x%2B20%7D%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7B%5Cdfrac%7B8x-32%7D%7Bx%5E2-4x-5x%2B20%7D-%5Cdfrac%7B9x-45%7D%7Bx%5E2-4x-5x%2B20%7D%3D%5Cdfrac%7B5%7D%7Bx%5E2-9x%2B20%7D%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7B%5Cdfrac%7B8x-32%7D%7Bx%5E2-9x%2B20%7D-%5Cdfrac%7B9x-45%7D%7Bx%5E2-9x%2B20%7D%3D%5Cdfrac%7B5%7D%7Bx%5E2-9x%2B20%7D%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7B%5Cdfrac%7B8x-32-%289x-45%29%7D%7Bx%5E2-9x%2B20%7D%3D%5Cdfrac%7B5%7D%7Bx%5E2-9x%2B20%7D%7D)
Numerators must be equal:
![\mathsf{8x-32-(9x-45)=5}\\\\ \mathsf{8x-32-9x+45=5}\\\\ \mathsf{8x-9x=5+32-45}\\\\ \mathsf{-x=-8}\\\\ \mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}](https://tex.z-dn.net/?f=%5Cmathsf%7B8x-32-%289x-45%29%3D5%7D%5C%5C%5C%5C%0A%5Cmathsf%7B8x-32-9x%2B45%3D5%7D%5C%5C%5C%5C%0A%5Cmathsf%7B8x-9x%3D5%2B32-45%7D%5C%5C%5C%5C%0A%5Cmathsf%7B-x%3D-8%7D%5C%5C%5C%5C%0A%5Cmathsf%7Bx%3D8%7D%5Cquad%5Clongleftarrow%5Cquad%5Ctextsf%7Bthis%20is%20the%20solution.%7D)
I hope this helps. =)
Tags: <em>rational equation fraction solution algebra</em>