<span>y = tan^−1(x2/4)</span>
tan(y) = x2/4
sec2(y) = x/2
y′ = xcos^2(y)/2
<span>cos^2(y) = <span>16x2+16</span></span>
<span>y′ = <span>8x/(<span>x2+16)
let u be x2+16
du is 2x dx
dy = 4 du / u
y = 4 ln (</span></span></span>x2 <span>+ 16)
y at x =0 = </span> 4 ln (<span>16) = 11.09</span>
14x + 10y = 72
14x + 4y = 96
6y = -24
6 6
y = -4
14x + 10y = 72
14x + 10(-4) = 72
14x - 40 = 72
+ 40 + 40
14x = 112
14 14
x = 8
(x, y) = (8, -4)
Answer:
Sorry if this is late, but it's 24mm2
Step-by-step explanation:
i got a 100 on the quiz
Answer:
$16.50
Step-by-step explanation:
