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BaLLatris [955]

2 years ago

6

1-cos(12x)=____. A. 2cos^2(12x) B. 2cos^2(6x) C. 2sin^2(12x) D. 2sin ^2(6x)

1 answer:

cluponka [151]2 years ago

8 0

By applying <em>trigonometric</em> expressions and <em>algebra</em> properties, the <em>trigonometric</em> equation 1 - cos 12x is equivalent to the <em>trigonometric</em> equation 2 · sin² 6x. (Correct choice: D)

<h3>How to simplify a trigonometric equation</h3>

Herein we have a trigonometric equation which has to be simplified. Simplification procedure consists in applying <em>trigonometric </em>expressions and <em>algebra</em> properties to transform the function from the form f(cos 12x) to the form f(cos 6x). Now we present the solution in detail:

1 - cos 12x Given
1 - cos² 6x + sin² 6x cos 2x = cos² x - sin² x / (- 1) · a = - a
1 - 1 + sin² 6x + sin² 6x cos² x + sin² x = 1 / (- 1) · a = - a
2 · sin² 6x Definitions of subtraction and addition / Existence of additive inverse / Modulative property / Result

By applying <em>trigonometric</em> expressions and <em>algebra</em> properties, the <em>trigonometric</em> equation 1 - cos 12x is equivalent to the <em>trigonometric</em> equation 2 · sin² 6x. (Correct choice: D)

To learn more on trigonometric equations: brainly.com/question/23599274

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Answer: Option D

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Step-by-step explanation:

A value $x_i$ is considered an outlier if

$x_i> Q_3 + 1.5IQR$

or

$x_i$

Where

$Q_3$ is the third quartile

$Q_1$ is the first quartile

IQR is the interquartile range.

$IQR = Q_3-Q_1$

In this case:

$Q_3=92\\Q_1=72$

So

$IQR = 92-72 =20$

$Q_3 + 1.5IQR = 92 + 1.5*20 = 122$

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Then the outlier values will be all those greater than 122 or less than 42

Therefore the answer is the option D.

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Step-by-step explanation:

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Step-by-step explanation:

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