From the given figure ,
RECA is a quadrilateral
RC divides it into two parts
From the triangles , ∆REC and ∆RAC
RE = RA (Given)
angle CRE = angle CRA (Given)
RC = RC (Common side)
Therefore, ∆REC is Congruent to ∆RAC
∆REC =~ ∆RAC by SAS Property
⇛CE = CA (Congruent parts in a congruent triangles)
Hence , Proved
<em>Additional comment:-</em>
SAS property:-
"The two sides and included angle of one triangle are equal to the two sides and included angle then the two triangles are Congruent and this property is called SAS Property (Side -Angle-Side)
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Answer: A cardboard box without a lid is to have a volume of 32,000 cubic cm. Find the dimensions that minimize the amount of cardboard used
. ans: base 40 x 40, height = 20
Solution:
The typical box might look like the one below
where . In addition we have xyz = 32000 ,so we need to minimize .
We have,
From the geometry of the problem so y = x. So or x = 40.
Finally, y = x = 40 and z = 32000/(xy)=20.
Answer:
ABD= 58
BDC= 32
Step-by-step explanation:
complementary = 2 angles equal 90 degrees.
8y+2=90
Subtract 2 both sides.
8y=88
y=11
That's not all, put y into the equations.
ABD
5(11)+3
Multiply
55+3=58
BDC
3(11)-1
MULTIPLY
33-1
SUBTRACT
32
Answer:
a. 59049
b. 15120
Step-by-step explanation:
<u>a. If digits can be repeated:</u>
- There are 9 possible numbers for each digit
That is: possible 5-digit pass codes are 9×9×9×9×9=
=59049
<u>b. If digits cannot be repeated.</u>
There is
- 9 possibility for the first digit,
- 8 possibility for the second digit
- 7 possibility for the third digit
- 6 possibility for the fourth digit
- 5 possibility for the fifth digit
That is: possible 5-digit pass codes are 9×8×7×6×5=15120
