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Likurg_2 [28]
2 years ago
9

Solve For X. 5 - 2x^2 = -15

Mathematics
2 answers:
Dvinal [7]2 years ago
4 0

Answer:

\sqrt{10}

Step-by-step explanation:

5 - 2x^2 = -15

2x^2 = 20

x^2=10

x= \sqrt{10}

DiKsa [7]2 years ago
3 0
-15-5= -20
Thus, -2x^2 = -20
Then -20/-2= 10
So, x^2 = 10
When you square root both of them, the answer is root 10
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Can someone help with this?
Bumek [7]
4.5/3 = x/5

then:

x = 5 * 4.5 / 3 = 15/2 = 7.5


hope that helps

6 0
4 years ago
What is the measurement of BC to the nearest centimeter?
77julia77 [94]

Answer:

a   8

Step-by-step explanation:

You are given two sides and the included angle. Since you don't have any side and the opposite angle, you must use the law of cosines.

a^2 = b^2 + c^2 - 2bc\cos A

a^2 = 5^2 + 11^2 - 2(5)(11)\cos 39^\circ

a^2 = 25 + 121 - 110\cos 39^\circ

a^2 = 60.51

a = 7.779

Answer: a = 8 cm

7 0
3 years ago
Round 10,031.464 to the nearest hundred.
insens350 [35]

Answer:

10,031.46

Rounded to the nearest 0.01 or

the Hundredths Place.

Step-by-step explanation:

7 0
4 years ago
CALCULUS: For an object whose velocity in ft/sec is given by v(t) = sin(t), what is its distance, in feet, travelled on the inte
rodikova [14]

The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.

To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

\mathrm{distance} = \displaystyle\int_1^5 |\sin(t)| \,\mathrm dt

By definition of absolute value,

|\sin(t)|=\begin{cases}\sin(t)&\text{for }\sin(t)\ge0\\-\sin(t)&\text{for }\sin(t)

Over this particular integration interval,

• sin(<em>t</em> ) ≥ 0 for 1 ≤ <em>t</em> < <em>π</em>, and

• sin(<em>t</em> ) < 0 for <em>π</em> < <em>t</em> ≤ 5

so you end up splitting the integral at <em>t</em> = <em>π</em> as

\mathrm{distance} = \displaystyle\int_1^\pi \sin(t)\,\mathrm dt + \int_\pi^5 (-\sin(t))\,\mathrm dt

Now compute the distance:

\mathrm{distance} = -\cos(t)\bigg|_1^\pi + \cos(t)\bigg|_\pi^5

\mathrm{distance} = -(\cos(\pi) - \cos(1)) + (\cos(5) - \cos(\pi))

\mathrm{distance} = -2\cos(\pi) + \cos(1) + \cos(5) \approx 2.82

making B the correct answer.

7 0
3 years ago
Solve 3x + 9 = 24.<br> A. x = 5<br> B. x = 11<br> C. x = 12<br> D. x = 18
DIA [1.3K]

Answer:

A. x = 5

Step-by-step explanation:

3x + 9 = 24

→ Minus 9 from both sides

3x = 15

→ Divide both sides by 3

x = 5

4 0
2 years ago
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