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lilavasa [31]
2 years ago
15

If the volume of the pyramid shown is 360 inches cubed, what is its height?

Mathematics
2 answers:
GenaCL600 [577]2 years ago
5 0
<h3>Answer: 9 inches (choice D)</h3>

Work Shown:

V = volume of pyramid

V = (1/3)*(area of base)*(height)

V = (1/3)*(12*10)*h

V = (1/3)*120h

V = 40h

Set this equal to the given pyramid volume 360 cubic inches and solve for h

40h = 360

h = 360/40

h = 9

MariettaO [177]2 years ago
3 0

Answer:

9 inches

Step-by-step explanation:

The formula for the volume of a rectangular pyramid is

Here we have volume (V), base (L), and width (W)

V = 360 in³, L = 12 in, W = 10 in

We need to manipulate the volume equation to solve for the height (H)

First we need to multiply both sides by 3 to get rid of the fraction:  3V = L×W×H

Then we need to divide both sides by (L×W) to get:

Now we can plug in the given values:

The height is 9 inches

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What is the x coordinate of the solution of the system? 2x+y=15 and x-y=3
Varvara68 [4.7K]

x - y = 3

x = 3 + y

x -3 = y

y = x-3

put it in 1st equation

2x +y = 15

2x + x - 3 = 15

3x - 3 = 15

3x = 15+3 = 18

x = 18/3 = 6

x = 6

6 0
3 years ago
I toss an unfair coin 12 times. This coin is 65% likely to show up heads. Calculate the probability of the following.
mars1129 [50]

Answer:

a. 0.0368

b. 0.99992131

c. 0.2039

d. 0.0048

e. 0.6533

Step-by-step explanation:

Let the probability of obtaining a head be p = 65% = 13/20 = 0.65. The probability of not obtaining a head is q = 1 - p = 1 -13/20 = 7/20 = 0.35

Since this is a binomial probability, we use a binomial probability.

a. The probability of obtaining 11 heads is ¹²C₁₁p¹¹q¹ = 12 × (0.65)¹¹(0.35) = 0.0368

b. Probability of 2 or more heads P(x ≥ 2) is

P(x ≥ 2) = 1 - P(x ≤ 1)

Now P(x ≤ 1) = P(0) + P(1)

= ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹

= (0.65)⁰(0.35)¹² + 12(0.65)¹(0.35)¹¹

= 0.000003379 + 0.00007531

= 0.0007869

P(x ≥ 2) = 1 - P(x ≤ 1)

= 1 - 0.00007869

= 0.99992131

c. The probability of obtaining 7 heads is ¹²C₇p⁷q⁵ = 792(0.65)⁷(0.35)⁵ = 0.2039

d. The probability of obtaining 7 heads is ¹²C₉q⁹p³ = 220(0.65)³(0.35)⁹ = 0.0048

e. Probability of 8 heads or less P(x ≤ 8) = ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹ + ¹²C₂p²q¹⁰ + ¹²C₃p³q⁹ + ¹²C₄p⁴q⁸ + ¹²C₅p⁵q⁷ + ¹²C₆p⁶q⁶ + ¹²C₇p⁷q⁵ + ¹²C₈p⁸q⁴

= = ¹²C₀(0.65)⁰(0.35)¹² + ¹²C₁(0.65)¹(0.35)¹¹ + ¹²C₂(0.65)²(0.35)¹⁰ + ¹²C₃(0.65)³(0.35)⁹ + ¹²C₄(0.65)⁴(0.35)⁸ + ¹²C₅(0.65)⁵(0.35)⁷ + ¹²C₆(0.65)⁶(0.35)⁶ + ¹²C₇(0.65)⁷(0.35)⁵ + ¹²C₈(0.65)⁸(0.35)⁴

= 0.000003379 + 0.00007531 + 0.0007692 + 0.004762 + 0.01990 + 0.05912 + 0.1281 + 0.2039 + 0.2367

= 0.6533

3 0
3 years ago
Help now pleaseeee!!!
Sliva [168]

Answer:

Step-by-step explanation:

Whitxh answer are u tryna get?

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3 years ago
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konstantin123 [22]
Hello,
First, we distribute the -4 to -6x + 14 to get a resulting expression of 24x - 56. Now, our total equation is -2x + 24x - 56 = 76. Next, we combine like terms on the left side of the equation, and that results in 22x - 56 = 76. Now, we add 56 to both sides to get 22x = 132. Finally, we divide both sides by 22 to get x = 6. Therefore, the value of x is 6. Hope this helps and have a great day!
5 0
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