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mestny [16]
3 years ago
10

Ray industries bought a touchscreen monitor for $1200 it is expected to depreciate at a rate of 25% per year what was the value

of the monitor be in three years round to the nearest dollar
Mathematics
1 answer:
max2010maxim [7]3 years ago
7 0

So for this problem, we will be using the exponential equation format, which is y = ab^x. The a variable is the initial value, and the b variable is the growth/decay.

Since our touchscreen starts off at a value of 1200, that will be our a variable.

Since the touchscreen is decaying in value by 25%, subtract 0.25 (25% in decimal form) from 1 to get 0.75. 0.75 is going to be your b variable.

In this case, time is our independent variable. Since we want to know the value 3 years from now, 3 is the x variable.

Using our info above, we can solve for y, which is the cost after x years.

y=1200*0.75^3\\y=506

In context, after 3 years the touchscreen will only be worth $506.

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Will give brainliest
Sonja [21]

The sum of the two <em>rational</em> equations is equal to (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²).

<h3>How to simplify the addition between two rational equations</h3>

In this question we must use <em>algebra</em> definitions and theorems to simplify the addition of two <em>rational</em> equations into a <em>single rational</em> equation. Now we proceed to show the procedure of solution in detail:

  1. (n + 5) / (n² + 3 · n - 10) + 5 / (3 · n²)      Given
  2. (n + 5) / [(n + 5) · (n - 2)] + 5 / (3 · n²)     x² - (r₁ + r₂) · x + r₁ · r₂ = (x - r₁) · (x - r₂)
  3. 1 / (n - 2) + 5 / (3 · n²)     Associative and modulative property / Existence of the multiplicative inverse
  4. [3 · n² + 5 · (n - 2)] / [3 · n² · (n - 2)]       Addition of fractions with different denominator
  5. (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²)       Distributive property / Power properties / Result

To learn more on rational equations: brainly.com/question/20850120

#SPJ1

4 0
2 years ago
Suppose p" must approximate p with relative error at most 10-3 . Find the largest interval in which p* must lie for each value o
goblinko [34]

Answer:

[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]

Step-by-step explanation

The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is

r = |p*-p|/|p|

we want r to be at most 10⁻³, thus

|p*-p|/|p| ≤ 10⁻³

|p*-p| ≤ |p|* 10⁻³

therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval  [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]

8 0
2 years ago
-4/9x=16/27 alguien que me ayude
Andre45 [30]
<h3>Answer</h3>

First multiply everything by 27

-  \frac{4}{9} x =  \frac{16}{27}  =  \\ 27 \times ( -  \frac{4 }{9}x) = 27 \times  \frac{16}{27}

Then approximate the terms with 27 if it's possible (27 and 9) (27 and 27)

3 \times (   - \frac{4}{1} ) = 16

So now multiply again

3 \times ( - 4) =  - 12

And you have

- 12x = 16

x =  -  \frac{16}{12}  =  -  \frac{4}{3}

You're welcome if it's right

4 0
3 years ago
What is the constant of the variation for the inverse variation?
Alisiya [41]

Answer:

2nd possible answer is the correct one; the const. of var. is 1/3.

Step-by-step explanation:

xy = 1/3 can be rewritten in inverse variation format:  Divide both sides by x to isolate y.  Then y = (1/3)(1/x).  The constant of (inverse) variation is 1/3.


4 0
3 years ago
Balu and Pumba shared 2/3 of a cake. Balu got to eat three times as much cake as Pumba. What fraction of the whole cake did Balu
MatroZZZ [7]

Answer:

In fraction, Balu ate 1/2 of the whole cake

Step-by-step explanation:

Balu and Pumba shared 2/3 of a cake.

Balu eats three times as much cake as Pumba.

So let's take the 2/3 they shared as a whole.

Let's Balu share be x

And pumbs share be y

X = 3y

But x + 3y = 2/3

Since x = 3y

Y = x/3

x + x/3 = 2/3

4x/3 = 2/3

X = (2*3)/(4*3)

X = 2/4

X = 1/2

Balu ate half of the whole cake

In fraction, Balu ate 1/2 of the whole cake

6 0
2 years ago
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