Answer:

Step-by-step explanation:
is the least steeped graph
- The greater the slope, the steeper the line.
- Also you use the absolute values of the slopes when determining the steepness.
- So here it would be:

- Now, arrange them from least to greatest:

As you can see,
is the smallest number/slope.
Hope this helps!
Answer:
y = e·x
Step-by-step explanation:
The equation of a line tangent to a curve at a point is conveniently written in the point-slope form. The slope is the derivative of the function at the point. For your function, the rules applicable to products and exponential functions apply.
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y = (e^x)(x^2 -2x +2
y' = (e^x)(x^2 -2x +2) +(e^x)(2x -2) . . . . . (uv)' = u'v +uv', (e^x)' = e^x
y' = (e^x)x^2 . . . . . simplify
For x=1, the slope is ...
y' = (e^1)(1^2) = e
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The point-slope form of the equation for a line is ...
y -k = m(x -h) . . . . . . line with slope m through point (h, k)
y -e = e(x -1) . . . . . . . line with slope 'e' through point (1, e)
y = e·x -e +e . . . . . add e
y = e·x . . . . . . . . . . equation of the tangent line
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<em>Additional comment</em>
It is often the case that ex is written when e^x is intended. We are trying to avoid that ambiguity here by writing the equation with an explicit "times" symbol.
The equation of the line is y = -2/3x - 3.
To find this, we first need to turn the intercepts into ordered pairs.
x intercept: (-4.5, 0)
y intercept: (0, -3)
Now we can use these two points and the slope equation to find slope.
m = (y2 - y1)/(x2 - x1)
m = (0 - -3)/(-4.5 - 0)
m = 3/-4.5
m = -2/3
Now that we have the slope, we can use slope intercept form to find the intercept.
y = mx + b
-3 = 2/3(0) + b
-3 = 0 + b
-3 = b
Which allows us to model the equation as y = -2/3x - 3
Answer:
can we get a bit more information
<span>lack of smoothness or regularity in a surface.
</span><span>difference in size, degree, circumstances
lack of equality
</span><span>the relation between two expressions that are not equal, employing a sign such as ≠ “not equal to,” > “greater than,” or < “less than.”</span>