3 years ago

Compare

"latex-formula"> and $11^{99}$ .

Mathematics

1 answer:

maxonik [38]3 years ago

8 0

A = 5¹⁴⁹
B = 11⁹⁹

Case 1: A>B
Result: True

Case 2: A=B
Result: False

Case 3: AResult: False

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$R(x)= \frac{(12+1)^2}{2}\ln(12+1)-\frac{(12+1)^2}{4}\\\\= \frac{(13)^2}{2}\ln(13)-\frac{(13)^2}{4}\\\\=\frac{169}{2}\ln(13)-\frac{169}{4}$

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