Given same lengths and slopes of the opposite sides and nature of the angle between adjacent sides, we have;
- The type of quadrilateral is a parallelogram
<h3>How can the type of quadrilateral be found?</h3>
The given points are;
L(-5, 4), M(2, 2), N(0, -3), S(-7, -1)
Lengths of the sides are;
Length of LM = √((2-(-5))²+(2-4)²) ≈ √(53)
Length of MN = √((2-0)²+(2-(-3))²) ≈ √(29)
Length of NS = √((0-(-7))²+((-3)-(-1))²) ≈ √(53)
Length of LS = √(((-7)-(-5))²+((-1)-4)²) ≈ √(29)
Therefore;
- The lengths of opposite sides are the same.
Slope of LM = (2-4)/(2-(-5)) = -2/7
Slope of MN = (2-(-3))/(0-2) = 5/2
Slope of NS = ((-3)-(-1))/(0-(-7)) = -2/7
Slope of LS = ((-1)-4)/(-7-(-5)) = 5/2
Therefore;
- The opposite sides are parallel, and
- The the adjacent sides are not perpendicular
The quadrilateral created by the points L(-5, 4), M(2, 2), N(0, -3), S(-7, -1) is therefore;
Learn more about parallelograms here:
brainly.com/question/1100322
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