Using the binomial distribution, it is found that there is a 0.5601 = 56.01% probability that the number having at least one VCR is no more than 8 but at least 6.00.
For each household, there are only two possible outcomes. Either it has at least one VCR, or it does not. The probability of a household having at least one VCR is independent of any other household, which means that the binomial distribution is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- 14 households, hence
. - 0.535 probability of having at least one VCR, hence
.
The probability of <u>at least 6 and no more than 8</u> is:

In which:




Then:

0.5601 = 56.01% probability that the number having at least one VCR is no more than 8 but at least 6.00.
A similar problem is given at brainly.com/question/24863377
Answer: It is 1/12
Step-by-step explanation:
There are a total of 12 cards. If you look at the table, there is only one yellow card that is even. So it is 1/12.
Answer:
Sol: In this question, firstly we have to make the first bracket as a complete square of the second bracket. This we can by adding 2.x.1/x which is equivalent to 2. Then the equation becomes:
6(x2 + 1/x2 +2) – 5(x + 1/x) = 50 { 38 + 6*2)
⇒ 6(x2 + 1/x2 +2) – 5(x + 1/x) – 50 = 0
Now put x + 1/x = y
⇒ 6y2 -5y -50 = 0
⇒ (2y +5)(3y-10)= 0
⇒ y=-5/2 or 10/3
As x is positive therefore, x + 1/x =10/3
On solving further you will get as x=3 or 1/3
Answer:
TRUE!!!!!!!!!!!!!!!!!! BRANLIST
Step-by-step explanation:
Use a calculator it’s 117