Answer:
what are you asking
Step-by-step explanation:
Since we have a cubic root, we're interested in factoring cubes inside the root, so that we can take them out. If we factor 648, we have

So, we have
![3x\sqrt[3]{648 x^4 y^8} = \sqrt[3]{3\times 6^3\cdot x^3\cdot x \cdot y^6\cdot y^2}=3x\cdot 6\cdot x\cdot y^2\sqrt[3]{3\cdot x\cdot y^2}](https://tex.z-dn.net/?f=3x%5Csqrt%5B3%5D%7B648%20x%5E4%20y%5E8%7D%20%3D%20%5Csqrt%5B3%5D%7B3%5Ctimes%206%5E3%5Ccdot%20x%5E3%5Ccdot%20x%20%5Ccdot%20y%5E6%5Ccdot%20y%5E2%7D%3D3x%5Ccdot%206%5Ccdot%20x%5Ccdot%20y%5E2%5Csqrt%5B3%5D%7B3%5Ccdot%20x%5Ccdot%20y%5E2%7D)
And the result simplifies to
![18x^2y^2\sqrt[3]{3xy^2}](https://tex.z-dn.net/?f=18x%5E2y%5E2%5Csqrt%5B3%5D%7B3xy%5E2%7D)
In the parallelogram ABCD, diagonals AC and BD intersect at point E.
According to the definition of parallelogram, opposite sides are equal and parallel to each other. That means, AB = DC
Now as AB and DC are parallel, so according to the property of Alternate Interior Angles, we will get:
∠EAB = ∠ECD and ∠EBA = ∠EDC
Thus , in two triangles ΔABE and ΔDCE, two angles and one side are equal. So, ΔABE and ΔDCE are congruent to each other.
That means, AE = CE and BE = DE
So, AE is congruent to CE and BE is congruent to DE