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nata0808 [166]
3 years ago
11

Type​ A, type​ B, and type C lightbulbs are lasting longer today than ever before. On​ average, the number of bulb hours for a t

ype C bulb is 18 times the number of bulb hours for a type B bulb. The number of bulb hours for a type A bulb is 1100 less than the type B bulb. If the total number of bulb hours for the three types of lightbulbs is 78900​, find the number of bulb hours for each type.
Mathematics
1 answer:
NNADVOKAT [17]3 years ago
3 0

Answer:

Step-by-step explanation:

Let and be independent random variables representing the lifetime (in 100 hours) of Type A and Type B light bulbs, respectively. Both variables have exponential distributions, and the mean of X is 2 and the mean of Y is 3.

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dimulka [17.4K]
Since perimeter is all of the sides added up.. 
And we have 
side 1 = 4in
side 2 = 4in 
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side 6 = 6in 

Lets just add them all up 
4 + 4 + 5 + 6 = 19 

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4 years ago
I need help on my 3.3.6 Journal: Breakdown Ahead apex.
insens350 [35]

Answer:

pg. 1

teresa: use difference of 2 squares

rico: 6561 is not a perfect square

pg. 2

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problem 1: (x^4-81)^2=(x^2-9)^4=(x-3)^8

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Step-by-step explanation:

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7 0
3 years ago
I am not sure how sigma notation works, can somebody explain how to solve this? It isn't the second choice.
Masja [62]

Answer:

first answer is correct

Step-by-step explanation:

Hello, we want to write 2 + 4 + 6 + ... + 20

for n = 1, 2n = 2*1 =2

for n = 2, 2n = 2*2=4

for n = 3, 2n=2*3=6

etc

so

\displaystyle \sum_{n=1}^{10} {2n} = 2*1 + 2*2 +2*3+2*4+...+2*10=2+4+6+8+...+20

thanks

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3 years ago
Rearrange the equation e-5=2f to e=
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-2f-5=-e

then you divide by the -1 to get the positive e

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4 years ago
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