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nata0808 [166]
3 years ago
11

Type​ A, type​ B, and type C lightbulbs are lasting longer today than ever before. On​ average, the number of bulb hours for a t

ype C bulb is 18 times the number of bulb hours for a type B bulb. The number of bulb hours for a type A bulb is 1100 less than the type B bulb. If the total number of bulb hours for the three types of lightbulbs is 78900​, find the number of bulb hours for each type.
Mathematics
1 answer:
NNADVOKAT [17]3 years ago
3 0

Answer:

Step-by-step explanation:

Let and be independent random variables representing the lifetime (in 100 hours) of Type A and Type B light bulbs, respectively. Both variables have exponential distributions, and the mean of X is 2 and the mean of Y is 3.

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The fourth grade student at Riverside school are going on a field trip . There are 68 student on each of the four buses. How man
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This answer is 272 I know because I did it vertically
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Find the measure of a 6.<br> 102<br> 78<br> 46 = [?]
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Answer:

102°

Step-by-step explanation:

They're still corresponding angles... have you read any of these explanations?...

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RESUELVE EL SIGUINTE PORBLEMA En la escuela "Soy Feliz porque soy diverso", hay 230 estudiantes en total. De estos, 35 son mujer
Tanzania [10]

Answer:

1) a. 195 are males

b. Males are the 85 %

2) 1/2

Step-by-step explanation:

Number of all the students: 230

35 are females

x are males

Then 35 + x = 230

x = 230 - 35 → 195

To determine the amount of males, from the total we apply the percent.

Percent = (Amount of males / Total of students) . 100

% = (195 / 230) . 100 = 85 %

2. In first place, Maria spent 13 for the book.

In second place, Maria spent 29 for the pencil box.

In total, she has spent 13+29 = 42

But, how many dolars have the grandpa gave to her?.

We can also apply percent and fractions, where:

(Book / Total) + (Pencil box/Total) + (What she did not spend/Total) = 1

13 + 29 + x = T

13/T + 29/T + x/T = 1, in conclussion x = 42

Total of money given = 84

Then, Maria has not spent the half of money→ 1/2

7 0
3 years ago
List the first 5 multiples, and find ALL the factors of 13
kvasek [131]

Answer:


13,26,39,52,65,78 are the multiples 13 and 1 are the all of the factors


7 0
3 years ago
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Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)
Svet_ta [14]
<h2>Answer:</h2>

\boxed{x=1, \y=-1, \ z=2}

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}

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\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}

Step 4: solve for z, then for y, then for x:

\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}

-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}

By substituting y=-1 \ and \ z=2 into the first equation, we get the x. So:

x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}

6 0
4 years ago
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