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Sveta_85 [38]
1 year ago
12

Simplify 25p^6q^9 / 45p^8q^4. write answer using a positive exponent

Mathematics
1 answer:
sleet_krkn [62]1 year ago
5 0

The simplification of 25p^6q^9 / 45p^8q^4 using a positive exponent;

  • Division is 5p^6 q^9 / 9p^8 q^4
  • Elevated form is  5/9 p^-2 q^5

<h3>What are algebraic expressions?</h3>

Algebraic expressions are expressions made up of factors, variables, terms, coefficients and constants.

They are also comprised of arithmetic operations such as addition, subtraction, multiplication, division, etc

We also know that index forms are also know as standard forms.

They are mathematical expressions showing the power of exponent of a variable in terms of another variable.

Given the index algebraic forms;

25p^6q^9 / 45p^8q^4

Using the rule of indices, we take the negative exponent of the divisor and multiply through.

We have;

5p^6 q^9 × 9p^-8 q^-4

Add exponential values

5/9 p^6-8 q^9 -4

5/9 p^-2 q^5

Thus, the expression is simplified to 5/9 p^-2 q^5

Learn more about index forms here:

brainly.com/question/15361818

#SPJ1

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6 0
2 years ago
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y
kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69  104  125  129  60  64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

  • M is the sample mean weight of the wild mountain lions (\frac{69 +104 +125 +129+60 +64}{6} =91.8)
  • ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
  • s is the standard deviation of the sample(31.4)
  • N is the sample size (6)

Thus, ME=\frac{1.30*31.4}{\sqrt{6} } ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

3 0
3 years ago
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