There are 10 bird feeders in total. So if Bob builds 10 Jake builds 0. If Bob builds 9 then Jake builds 1. If Bob builds 8 then Jake builds 2 and so on.
Y=4(x-3)+6 is the form that is easiest to get then you can multiply it out and get y=4x-6 can rearrange to the standard form which would be y-4x=-6 because in standard form the x and y are on the same side
sqrt(2x+1) when x=11
sqrt(2*11+1)
sqrt(22+1)
sqrt(23)
4.79583
to the nearest tenth
4.8
sqrt(4x+1) + sqrt(2x) when x=8
sqrt(4*8+1) + sqrt(2*8)
sqrt(32+1) + sqrt(16)
sqrt(33) + 4
5.7446 +4
9.7446
rounding to the nearest tenth
9.7
Answer:
Step-by-step explanation:
<h3><u>Given data:</u></h3>
Theta = θ = 35°
Radius = r = 10 ft.
<h3><u>Required:</u></h3>
Arc length = ?
<h3><u>Formula:</u></h3>
<h3><u>Solution:</u></h3>
Put the givens in the above formula
![\displaystyle Arc \ length = 2 (3.14)(10)(\frac{35}{360} )\\\\Arc \ length = 2(3.14)(10)(0.097)\\\\Arc \ length = 6.11 \ ft.\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Arc%20%5C%20length%20%3D%202%20%283.14%29%2810%29%28%5Cfrac%7B35%7D%7B360%7D%20%29%5C%5C%5C%5CArc%20%5C%20length%20%3D%202%283.14%29%2810%29%280.097%29%5C%5C%5C%5CArc%20%5C%20length%20%3D%206.11%20%5C%20ft.%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
For all the dogs: you have 2.65+2.46+3.67+2.91 = 11.69%
Now, the probability of getting a chihuahua would be 3.44/11.69=0.2942= 24.92
Step-by-step explanation:
there ya go
