Answer:
The x-coordinate of the point changing at ¼cm/s
Step-by-step explanation:
Given
y = √(3 + x³)
Point (1,2)
Increment Rate = dy/dt = 3cm/s
To calculate how fast is the x-coordinate of the point changing at that instant?
First, we calculate dy/dx
if y = √(3 + x³)
dy/dx = 3x²/(2√(3 + x³))
At (x,y) = (1,2)
dy/dx = 3(1)²/(2√(3 + 1³))
dy/dx = 3/2√4
dy/dx = 3/(2*2)
dy/dx = ¾
Then we calculate dx/dt
dx/dt = dy/dt ÷ dy/dx
Where dy/dx = ¾ and dy/dt = 3
dx/dt = ¾ ÷ 3
dx/dt = ¾ * ⅓
dx/dt = ¼cm/s
The x-coordinate of the point changing at ¼cm/s
Addition is defined as one of the main basic operation of mathematics. Addition is also defined as the process of adding one of more numbers. For the addition operation, there are many number of properties used. In that, one of the property is known as the commutative property of addition. It states that the change of order does not change the value of addition.
Commutative property of addition is true for all types of numbers including imaginary numbers. So you can pretty much use any numbers ex.2 + 3 = 3 + 2
Answer:
The length is 5.2 and the width is 3 and the area is 15.6
Step-by-step explanation:
To get the area just multiply width by length
33.3333333333333333333333333333333333333333333% continue
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2x^2-4x+2=x+2. 2x^2-4x+2-x-2=0. 2x^2<span>-3x-0=0. use quadratic formula = </span>(-b+- squareroot(b^2-4ac))/2a. so ur a=2<span> b=-3 c=0. hope this helped</span>